Answer:
8.60 * 
atoms N2
Explanation:
We want to convert grams to moles and then moles to atoms.
First, we convert grams of nitrogen gas (which is N2) to moles. To do so, we need the molar mass of N2, which is just 14.01 * 2 = 28.02 g.
40 g N2 * 
= 1.43 mol N2
Now, we need to convert moles to atoms by using Avogadro's number, which is 
:
1.43 mol N2 * 
= 8.60 * atoms N2
Thus, the answer is 8.60 * atoms N2.
Answer:
A. 15859.2 L or 15900 L
B. 0.629 mol
Explanation:
At STP, one mole is equal to approximately 22.4 L
L or mL is volume, so you are attempting to solve for L or mL.
A.
708 mol x (22.4 L/1 mol) = 15859.2 L (w/ significant figures included - 15900 L)
B.
(14.1 L) x (1 mole/ 22.4 L) = 0.629 mol.
Answer:
Molarity = 0.5 M
Explanation:
Given data:
Mass of NaCl = 2.7 g
Volume = 100 mL(100×10⁻³L)
Molarity of solution = ?
Solution:
Formula:
Molarity = number of moles / volume in litter
Number of moles:
Number of moles = mass/ molar mass
Number of moles = 2.7 g/ 58.5 g/mol
Number of moles = 0.05 mol
Molarity = number of moles / volume in litte
Molarity = 0.05 mol / 100×10⁻³L
Molarity = 0.5 M
The mass of GeCl4 that would be formed will be 1.51 g
<h3>Stoichiometric calculations</h3>
From the balanced equation of the reaction:
Ge (s) + 2Cl2 (g) →GeCl4
The mole ratio of Ge and Cl2 is 1:2.
Mole of 1.0 g Ge: 1/72.64
= 0.01377 mole
Mole of 1.0 g Cl2 = 1/71
= 0.01408 mole
Thus, Cl2 is limiting.
Mole ratio of Cl2 and GeCl4 = 2:1
Equivalent mole of GeCl4 = 0.01408/2
= 0.0070 mole
Mass of 0.0070 mole GeCl4 = 0.0070 x 214.4
= 1.51 g
More on stoichiometric calculations can be found here: brainly.com/question/8062886
