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Paladinen [302]
1 year ago
12

How does the height of a ramp affect the time it takes for an object to move down the ramp? please explain each one below:

Physics
1 answer:
weqwewe [10]1 year ago
7 0

The greater the height of a ramp, the shorter the time it takes for an object to move down the ramp.

The greater the amount of salt, the In addition the larger the longer it takes water to boil.

An increase in volume of water increases the time it takes to boil and vice versa.

Increase in the length of the paper airplane, the farther it will fly.

Jumping Jack increases the heart rate.

<h3>How does the height of a ramp affect the time it takes for an object to move down the ramp?</h3>

A ramp is an inclined plane which is a form of simple machine that is used to lift heavy objects off the floor or to lower heavy objects down.

The greater the height of a ramp, the shorter the time it takes for an object to move down the ramp due to increased acceleration.

<h3>How does the amount of salt affect how long it takes water to boil?</h3>

The addition of solutes to pure solvent raises the boiling point of the solute.

Therefore, the greater the amount of salt, the In addition the larger the longer it takes water to boil.

<h3>How does the volume of water affect how long it will take to boil?</h3>

The mass of water increases with increase in volume of water.

Therefore, an increase in volume of water increases the time it takes to boil and vice versa.

<h3>How does the length of a paper airplane affect how far it will fly?</h3>

For a paper airplane the larger its wings, the greater the lift generated.

The greater the lift, the farther the paper airplane will fly.

Therefore, an increase in the length of the paper airplane, the farther it will fly.

<h3>How do jumping jacks affect your heart rate?</h3>

Exercise increases the heart rate.

Jumping jack is a for of exercise. Therefore, Jumping Jack increases the heart rate.

Learn more about ramp and inclined plane at: brainly.com/question/10352783

#SPJ1

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Answer:

Emax = 0.055V

Imax = 7.86mA

Explanation:

See attachment below.

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3 years ago
What s physics?
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7 0
4 years ago
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Which of the following contains the majority of the mass in the solar system?
Bingel [31]
First think which has less mass in the solar system. The sun is the largest object in the solar system, so the answer is C. the sun. Hope I helped! :P
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3 years ago
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A car has a mass of 1.00 × 103 kilograms, and it has an acceleration of 4.5 meters/second2. What is the net force on the car?
aksik [14]

ANSWER


C. F=4.5 \times10^3. newtons


EXPLANATION


According to Newton's second law,



F_{net}=ma, where



m=1.00\times 10^3kg is the mass measured in kilograms.


and


a=4.5ms^{2} is the acceleration in metres per second square.



We substitute these values to obtain,


F=1.00\times10^3 \times 4.5.



We rearrange to get,


F=1.00\times4.5 \times10^3.


We multiply out the first two numbers and leave our answer in standard form to get,



F=4.5 \times10^3 N.



The correct answer is C


3 0
4 years ago
While standing on the edge of the grand canyon, you see a rattlesnake and scream. You hear the echo of the scream off canyon flo
bezimeni [28]

Answer:

1904 m

Explanation:

\pink{\frak{Given}}\begin{cases} \textsf{ You scream after seeing a rattle snake  .}\\\textsf{Scream is heard after 11.2 s .} \end{cases}

Here we need to find out the depth of the canyon . When you will scream after seeing a snake , the sound produced will travel till the end of the canyon and after hitting the end , it will travel back to you .

  • So if the depth of the canyon is d (say) , then the total distance travelled by the sound wave will be d + d = 2d .

And we know that the speed of the sound is approximately 340m/s in air , so we can use the formula distance = speed * time to calculate the depth of the canyon . So ,

\sf \longrightarrow Distance = (Speed)(Time) \\

\sf \longrightarrow 2d = 340m/s * 11.2 s\\

\sf \longrightarrow d = \dfrac{340m/s * 11.2s}{2} \\

\sf \longrightarrow \boxed{\bf Depth_{canyon}= 1904m }\\

6 0
2 years ago
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