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gregori [183]
2 years ago
13

How much heat energy would be needed to raise the temperature of a 15.0 g sample of iron [Specific Heat = 0.448 J/(g°C)] from 22

.0°C to 100.0°C?1. 524J2. 11J3. 249J4. 8495. 201J
Chemistry
1 answer:
Pepsi [2]2 years ago
5 0

Answer:

524\text{ J}

Explanation:

Here, we want to get the amount of heat energy needed

Mathematically:

Q\text{ = mc}\Delta T

where:

Q is the amount of energy that we want to calculate

m is the mass of the iron sample which is 15 g

c is the specific heat capacity which is 0.448 J/g°C

ΔT is the change in temperature which is (100-22) = 78°C

Substituting the values, we have it as:

Q\text{ = 15 }\times\text{ 0.448 }\times\text{ 78 = 524.16 J}

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1) We need to convert 12.0 g of H2 into moles of H2, and <span> 74.5 grams of CO into moles of CO
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<span>2) Now we can use reaction to find out what substance will react completely, and what will be leftover. 

                                  CO       +         2H2   ------->      CH3OH  
                                 1 mol              2 mol
given                        2.66 mol          6 mol (excess)

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We see that H2 will be leftover, because for 6 moles H2  we need 3 moles CO, but we have only 2.66 mol  CO.
So, CO will react completely, and we are going to use CO to find  the mass of CH3OH.

3)                              </span>CO       +         2H2   ------->      CH3OH  
                                 1 mol                                        1 mol
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4) We have 2.66 mol CH3OH
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2.66 mol CH3OH * 32.0 g CH3OH/ 1 mol CH3OH =  85.12 g CH3OH
<span>
Answer is </span>D) 85.12 grams.
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A 100. 0 ml sample of 0. 10 m nh3 is titrated with 0. 10 m hno3. Determine the ph of the solution after the addition of 100. 0 m
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This neutralization occurs as the acid is added to the base:

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The initial moles of NH3present is given by,

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The number of moles of

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