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gregori [183]
2 years ago
13

How much heat energy would be needed to raise the temperature of a 15.0 g sample of iron [Specific Heat = 0.448 J/(g°C)] from 22

.0°C to 100.0°C?1. 524J2. 11J3. 249J4. 8495. 201J
Chemistry
1 answer:
Pepsi [2]2 years ago
5 0

Answer:

524\text{ J}

Explanation:

Here, we want to get the amount of heat energy needed

Mathematically:

Q\text{ = mc}\Delta T

where:

Q is the amount of energy that we want to calculate

m is the mass of the iron sample which is 15 g

c is the specific heat capacity which is 0.448 J/g°C

ΔT is the change in temperature which is (100-22) = 78°C

Substituting the values, we have it as:

Q\text{ = 15 }\times\text{ 0.448 }\times\text{ 78 = 524.16 J}

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Answer:

1. The balanced molecular equation is given below:

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2. The net ionic equation is given below:

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Explanation:

1. The balanced molecular equation

Na2SO4(aq) + Ba(NO3)2(aq) —> BaSO4(s) + NaNO3(aq)

The above equation can be balance as follow:

Na2SO4(aq) + Ba(NO3)2(aq) —> BaSO4(s) + NaNO3(aq)

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Na2SO4(aq) + Ba(NO3)2(aq) —>

2Na^+(aq) + SO4^2-(aq) + Ba^2+(aq) + 2NO3^-(aq) —> BaSO4(s) + 2Na^+(aq) + 2NO3^-(aq)

Cancel the spectator ions i.e Na^+ and NO3^- to obtain the net ionic equation.

SO4^2-(aq) + Ba^2+(aq) —> BaSO4(s)

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