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Novay_Z [31]
3 years ago
8

Aptitude is the capacity to learn a particular skill or acquire a particular body of knowledge. Please select the best answer fr

om the choices provided T F
Chemistry
2 answers:
zhannawk [14.2K]3 years ago
8 0

Answer:

true

Explanation:

Luden [163]3 years ago
4 0
<h2>Answer:</h2>

True

<h2>Explanation:</h2>

we can describe aptitude as an innate ability of a person to do something. There are different aptitude test in which we test the skills and ability to do different work or his attitude toward success or failure.

So, we can say that aptitude is the capacity to learn a particular skill or acquire a particular body of knowledge.

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Who uses chemicals ?
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Is there answer choices ??
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3 years ago
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Use the molar bond enthalpy data in the table to estimate the value of Δ∘rxn
MakcuM [25]

Answer:

ΔH°rxn = - 433.1 KJ/mol

Explanation:

  • CH4(g) + 4Cl2(g) → CCl4(g) + 4HCl(g)

⇒ ΔH°rxn = 4ΔH°HCl(g) + ΔH°CCl4(g) - 4ΔH°Cl2(g) - ΔH°CH4(g)

∴ ΔH°Cl2(g) = 0 KJ/mol.....pure element in its reference state

∴ ΔH°CCl4(g) = - 138.7 KJ/mol

∴ ΔH°HCl(g) = - 92.3 KJ/mol

∴ ΔH°CH4(g) = - 74.8 KJ/mol

⇒ ΔH°rxn = 4(- 92.3 KJ/mol) + (- 138.7 KJ/mol) - 4(0 KJ/mol) - (- 74.8 KJ/mol)

⇒  ΔH°rxn = - 369.2 KJ/mol - 138.7 KJ/mol - 0 KJ/mol + 74.8 KJ/mol

⇒ ΔH°rxn = - 433.1 KJ/mol

4 0
3 years ago
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In a titration, 25.0 mL of 0.500 M KHP is titrated to the equivalence point with NaOH. The final solution volume is 53.5 mL. Wha
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M1v1=m2v2 
m2=(m1v1)/v2 
Where m is the molarities and v is the volumes
<span>m2=(25.0*0.500)/53.5
m2=12.5/53.5
m2=0.2336
by rounding off:
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so the answer is C: 0.234 M</span>
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nadya68 [22]

Answer:

Bacteria reproduce by binary fission. In this process the bacterium, which is a single cell, divides into two identical daughter cells. Binary fission begins when the DNA of the bacterium divides into two (replicates). ... Each daughter cell is a clone of the parent cell.

Explanation:

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What is the term for different “jobs” that different cells perform in a multicellular organism?
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A.
functions
B.
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