The mass of 
that would be formed will be 18.22 grams
<h3>Stoichiometric calculations</h3>
Let us first look at the balanced equation of the reaction:
The mole ratio of Y to 
is 2:3.
Mole of 10.0 grams of Y = 10/88.9 = 0.11 moles
Mole of 10.0 grams = 10/71 = 0.14 moles
3/2 of 0.11 = 0.165. Thus, is limiting in availability.
Mole ratio of and = 3:2
Equivalent mole of = 2/3 x 0.14 = 0.093 moles.
Mass of 0.093 moles =0.093 x 195.26 = 18.22 grams
More on stoichiometric calculations can be found here: brainly.com/question/27287858
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Answer:
b)The molar mass of the particles.
Explanation:
The rate of effusion of a gas is inversely proportional to the square root of its molar mass (Graham's law), a relationship that closely approximates the rate of diffusion. As a result, light gases tend to diffuse and effuse much more rapidly than heavier gases.
Answer is B) - neutrons.
Both protons and neutrons contribute to the mass of an atom. But ₈¹⁷O atom has atomic number as 8. Hence, number of protons is 8. Atomic mass of the given atom is 17.
Atomic mass = number of protons + number of neutrons
Hence, number of neutrons in the given atom is 17 - 8 = 9.
So, the number of neutrons is greater than the number of protons. Hence the greatest composition of ₈¹⁷O atom is neutrons by mass.
