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Doss [256]
1 year ago
7

a solution is to be prepared with a sodium ion concentration of 0.555 mol/l. what mass of sodium sulfate (g) is needed to prepar

e 2.00 liters of such a solution?
Chemistry
1 answer:
seraphim [82]1 year ago
3 0

Mass of sodium sulfate (g) is needed to prepare 2.00 liters of such a solution is  78.122.

Sodium Sulfate =N a_2 \mathrm{So}_4$.

$[\mathrm{Na}+]=0.555 \mathrm{mo} / / \mathrm{L}$

$\mathrm{mol} \mathrm{Nat}=0.555 \times2 =1.11 \mathrm{~mol}$

mol \mathrm{Nu}_2 \mathrm{Su}_4=\frac{1.11}{2}=0.55 \mathrm{~mol}$.

mol $\mathrm{Na}_2 \mathrm{So}_4=m_0 \times m \omega$ = 0.55 *142.04=78.122.

Drying organic liquids uses sodium sulphate. in powdered household laundry detergents as a filler. to eliminate minute air bubbles from molten glass as a fining agent. The decahydrate form of Glauber's salt is used as a laxative to eliminate medicines like acetaminophen from the body. The inorganic substance sodium sulfate and numerous related hydrates have the formula Na2SO4. White solids in all of their forms, they are very soluble in water. The decahydrate is a significant commodity chemical product, with a 6 million tonne yearly production.

To learn more about sodium sulfate  visit:brainly.com/question/4025301

#SPJ4

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50cm3 of a mixture of methane and hydrogen were mixed with excess oxygen and exploded, the product after cooling to the original
marin [14]

Answer:the initial composition of the reactants is

40cm^3 of CH4

40cm^3of H2

100cm^3 of H2O

Explanation:

Balanced reaction is

CH4 +H2+5/2O2______

CO2 +3H2O

Excess KOH at room temperature absorbs CO2 whose volume is given by 40cm^3 i.e the volume by which the solution decreases

So using Gay lussac combining ratio which states that gases combine in volumes that are in simple ratio to each other if gases.

Since CO2 in the equation is 1 mole

Means 1mole represent 40cm^3

So CH4:H2:O2 are in ratio of 1:1:5/2=(40:40:100)cm^3 respectively.

8 0
3 years ago
If you move 50 meters in 10 seconds, what is your speed? Givens: d= t= Unknown: Formula: Plug in: Solve:
marta [7]

Answer:

\huge\boxed{5 \ m/s}

Explanation:

<u>Given:</u>

Distance = S = 50 m

Time = t = 10 secs

<u>Unknown:</u>

Speed = v = ?

<u>Formula:</u>

v = S/t

<u>Plug In:</u>

S = 50 m , t = 10 secs

<u>Solution:</u>

v = 50 m / 10 secs

v = 5 m/s

Hope this helped!

<h2>~AnonymousHelper1807</h2>
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3 years ago
Read 2 more answers
How would you convert 500cc of 2M H2so4 in g/l and normality?​
Ann [662]

Concentration :

196 g/L and 4 N

<h3> </h3><h3>Further explanation</h3>

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

500 cc of 2M H₂SO₄

V = 500 cc = 0.5 L

mol H₂SO₄

\tt mol=M\times V=2\times 0.5=1

mass H₂SO₄ (MW = 98 g/mol)

\tt mass=mol\times MW=1\times 98=98~g

concentration in g/L :

\tt \dfrac{98}{0.5}=196~g/L

concentration in normality

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N = M x n (n=valence , amount of H⁺ or OH⁻)

so :

\tt N=2\times 2(n=2~for~H_2SO_4\rightarrow 2H^+)\\\\N=4

6 0
3 years ago
Calculate the percent activity of the radioactive isotope iodine-131 remaining after 3 half-lives.
vovangra [49]
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When, I-131 passes 2nd half life, activity of I-131 will be reduced to 25%

On passing, 3rd half-life, percent activity of the I-131 <span>remaining will be 12.5 %.</span>
3 0
4 years ago
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