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Evgen [1.6K]
10 months ago
9

Water can be made using the reversible reaction shown. Which change would

Chemistry
1 answer:
Ghella [55]10 months ago
5 0

Decreasing the temperature in the reaction vessel keep this reaction from shifting to form more of the product.

As we know that rate of reaction is directly proportional to the concentration of the reactant.

If we increase the concentration of H2 then the rate of reaction increases. So, we keep it constant. Therefore this option is wrong.

By removing the H₂O from the reaction vessel as it almost make no change in the reaction. This can be pursuited the reaction in which product again converted into product.

By increasing the temperature we increases the rate of reaction and equilibrium shift in the forward direction.

Thus, we concluded that by decreasing the temperature in the reaction vessel keep this reaction from shifting to form more of the product.

learn more about rate of reaction:

brainly.com/question/8592296

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The Pauli Exclusion Principle tells us that no two electrons in an atom can have the same four quantum numbers.
Anuta_ua [19.1K]

Answer:

See explanation

Explanation:

We can describe electrons using four sets of quantum numbers;

principal quantum number (n)

orbital quantum number (l)

magnetic quantum number (ml)

spin quantum number (ms)

Since no two electrons in an atom can have the same value for all four quantum numbers according to Pauli exclusion theory, for the orbitals given one possible value for each quantum number is shown below;

For 1s-

n = 1, l= 0, ml = 0, ms= 1/2

For 2s-

n= 2, l =0, ml=0, ms=1/2

For 1s and 2s orbitals, there is only one possible value for ml which is zero.

3 0
2 years ago
For the following reaction, the equilibrium constant Kc is 0.80 at a certain temperature. If the concentration of NO(g) and NOBr
velikii [3]

Answer:

[Br₂] =  1.25M

Explanation:

        2NO (g)  +  Br₂ (g)   ⇄   2NOBr (g)

Eq    0.80M            ?                0.80M

That's the situation told, in the statement.

Let's make the expression for Kc

Kc = [NOBr]² / [Br₂] . [NO]²

Kc = 0.80² / [Br₂] . [0.80]²

0.80 = 1 / [Br₂]

[Br₂] = 1 / 0.80 → 1.25

4 0
3 years ago
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