All categories

1 year ago

Water can be made using the reversible reaction shown. Which change would

Chemistry

1 answer:

Ghella [55]1 year ago

5 0

Decreasing the temperature in the reaction vessel keep this reaction from shifting to form more of the product.

As we know that rate of reaction is directly proportional to the concentration of the reactant.

If we increase the concentration of H2 then the rate of reaction increases. So, we keep it constant. Therefore this option is wrong.

By removing the H₂O from the reaction vessel as it almost make no change in the reaction. This can be pursuited the reaction in which product again converted into product.

By increasing the temperature we increases the rate of reaction and equilibrium shift in the forward direction.

Thus, we concluded that by decreasing the temperature in the reaction vessel keep this reaction from shifting to form more of the product.

learn more about rate of reaction:

brainly.com/question/8592296

#SPJ13

You might be interested in

How many atoms of carbon are in a pencil if the mass of carbon is 2.00 g.?

yulyashka [42]

so, There are (1/12.0)moles with each mole having 6.022 x10^23 atoms. 1 mole of carbon-12 has 6.02 x 1023 iotas.

3 0

3 years ago

How many atoms of hydrogen are represented in 2CH3CH2O?

sladkih [1.3K]

5 you can tell because it comes after the letter.

3 0

4 years ago

Read 2 more answers

A 1.00 g sample of n-hexane (C6H14) undergoes complete combustion with excess O2 in a bomb calorimeter. The temperature of the 1

Nadya [2.5K]

Answer:

-5,921x10⁶J/mol

Explanation:

Internal energy change (ΔU) for the reaction of combustion in the bomb calorimeter is:

ΔU = q calorimeter + q solution

Where:

q calorimeter is Ccal×ΔT (Ccal=4042J/°C) and (ΔT is 29,30°C-22,64°C=6,66°C)

q solution is c×m×ΔT (c= 4.184 J/g°C), (m=1502g H₂O), (ΔT is 29,30°C-22,64°C=6,66°C)

Replacing:

ΔU = 26920J + 41854J = 68774 J

This energy is per g of n-hexane, now, per mole of n-hexane:

$\frac{68774J}{1gHexane} *\frac{86,1g}{1mol}$ = -5,921x10⁶J/mol

-negative because the energy is produced-

I hope it helps!

5 0

4 years ago

Read 2 more answers

Given the electrochemical reaction as M(s)M2++(aq)Zn2+(aq)Zn(s); E° = +1.61 V. If the standard reduction potential of Zn2+→Z

Gnoma [55]

If two plus two is four then four plus four is two

6 0

4 years ago

Determine the density of nh3 gas at 435k and 1.00atm

goldenfox [79]

We assume that this gas is ideal. Therefore, we can use the ideal gas equation which is expressed as:

PV=nRT

We manipulate this equation to give us an expression which will correspond to density. We do as follows:

PV= nRT
P/RT = n/V where n = m/MM
P(MM) /RT = m/V = density
Density = 1.00 (17.03) / 0.08206 (435)
Density = 0.48 g / L

5 0

4 years ago