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Travka [436]
1 year ago
8

What is the molarity of a solution that contains 2.634 mol KCI in 25.2 L solution?O a. 0.105O b. 0.00141O c. 7.73O d. 105

Chemistry
1 answer:
Vikentia [17]1 year ago
4 0

Explanation:

To solve this question, we need to use the following formula:

M = n/V

So:

M = ??

n = 2.634 mol

V = 25.2 L

M = 2.634/25.2

M = 0.105 mol/L

Answer: a. 0.105

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which diagram best illustrates the ion-molecule attractions that occur when the ions of NaCl(s) are added to water
tatuchka [14]
Diagram is on the picture below.
Answer is: 1).
Sodium chloride is ionic compound and in the water dissociate in sodium cation (positive charge) and chloride anion (negative charge). Water is polar compound, oxagan has negative charge and hydrogen charge. Positive interact witn negative charge and negative with positive charge.

8 0
4 years ago
Analysis of a rock sample shows that it contains 6.25% of its original uranium-235. How old is the rock? How do you know?
nadya68 [22]

Answer:

2.82\cdot 10^9 y

Explanation:

A radioactive isotope is an isotope that undergoes nuclear decay, breaking apart into a smaller nucleus and emitting radiation during the process.

The half-life of an isotope is the amount of time it takes for a certain quantity of a radioactive isotope to halve.

For a radioactive isotope, the amount of substance left after a certain time t is:

m(t)=m_0 (\frac{1}{2})^{\frac{t}{\tau}} (1)

where

m_0 is the mass of the substance at time t = 0

m(t) is the mass of the substance at time t

\tau is the half-life of the isotope

In this problem, the isotope is uranium-235, which has a half-life of

\tau=7.04\cdot 10^8 y

We also know that the amount of uranium left in the rock sample is 6.25% of its original value, this means that

\frac{m(t)}{m_0}=\frac{6.25}{100}

Substituting into (1) and solving for t, we can find how much time has passed:

t=-\tau log_2 (\frac{m(t)}{m_0})=-(7.04\cdot 10^8) log_2 (\frac{6.25}{100})=2.82\cdot 10^9 y

5 0
4 years ago
The atomic symbol superscript 40 subscript 19 upper k. represents potassium-40 (k-40), a radioactive isotope that has 19 protons
Oksana_A [137]

Answer:

40/18AR

Explanation:

sorry my answer was late but i hope this helps someone else! I got it right on the test

8 0
2 years ago
What atomic or hybrid orbitals make up the sigma bond between c2 and c3 in propyne, chcch3 ? (c2 is the second carbon in the str
Anvisha [2.4K]

Answer:

\boxed{\text{$\sigma$(sp-sp$^{3}$); 180$^{\circ}$}}

Explanation:

(a) Hybridization of orbitals

See the Lewis structure of propyne in the first diagram below.

C1 is directly bonded to two other atoms (H and C2) so it is sp hybridized.

C2 is directly bonded to two other atoms (C1 and C3) so it is sp hybridized.

C3 is directly bonded to four other atoms (C2 and 3 H) so it is sp³ hybridized.

(b) C2-C3 Sigma Bond

See the atomic and molecular orbitals in the second picture below.

C3 is using its hybrid atomic orbitals to form sigma molecular bonds. The C2-C3 sigma bond is formed by the overlap of the C2 sp atomic orbital with the C3 sp³ atomic orbital to make a σ(sp-sp³) molecular orbital.

(c) Bond angles

C1 and C2 are sp hybridized. Since the angle between sp orbitals is 180°, all atoms directly attached the C1 and C2 must be in a straight line. The C-C-C bond angle is 180°.

4 0
3 years ago
Why is neon in the same group as helium on the periodic table
belka [17]
<span>The noble gases are the six elements that make up Group 18 of theperiodic table: helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and radon (Rn). At one time, this family of elements was also known as the rare gases.</span>
8 0
3 years ago
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