Answer:
The total energy to break all the bonds in 1 mole of 1-propanol, C₃H₈O, is 4411 kJ/mol
Explanation:
We note that propanol, C₃H₈O is also known as 1-propanol is written as follows;
CH₃CH₂CH₂OH which gives
CH₃-CH₂-CH₂-OH
Hence, the total number of bonds are;
C-H Bonds = 3 + 2 + 2 = 7
C-O Bonds = 1
O-H Bond = 1
C-C Bonds = 2
The bond energies are as follows;
C-H Bonds = 413 kJ/mol
C-O Bonds = 358 kJ/mol
O-H Bond = 468 kJ/mol
C-C Bonds = 347 kJ/mol
Energy required to break the bonds in 1-propanol is therefore;
C-H Bonds = 413 kJ/mol × 7 = 2,891 kJ/mol
C-O Bonds = 358 kJ/mol × 1 = 358 kJ/mol
O-H Bond = 468 kJ/mol × 1 = 468 kJ/mol
C-C Bonds = 347 kJ/mol × 2 = 694 kJ/mol
The total energy to break all the bonds in 1 mole of 1-propanol = 4411 kJ/mol.
Answer:
a would be the correct answer
Http://www.jiskha.com/search/index.cgi?query=what+will+happen+if+a+saturated+potassium+nitrate+solut...
please reffer
Answer:
[H+] = 1.66 x 
Explanation:
To find the [H+] concentration of a solution, we can use the formula:
![[H+] = 10^{-pH}](https://tex.z-dn.net/?f=%5BH%2B%5D%20%3D%2010%5E%7B-pH%7D)
Let's plug in the pH.
![[H+] = 10^{-3.78}](https://tex.z-dn.net/?f=%5BH%2B%5D%20%3D%2010%5E%7B-3.78%7D)
Evaluate the exponent.
[H+] = 1.66 x
Hope this helps!
