Would someone be able to answer the following questions:

1 answer:

5 0

A) 3x+5y-x+2y=
Group the same sexes
3x-x+5y+2y=
3x-x=2x
+5y+2y=7y
answer: 2x+7


B) 3g+5h+4g-2h=
Group the same sexes
3g+4g+5h-2h=
3g+4g=7g
+5h-2h=+3h
answer: 7g+3h

C) 4p+2p-3p=
Do not need to be grouped. Because everyone is of a gender
4p+2p=6p
6p-3p=3p
answer: 3p

D) 9s-5s+2s-s=
Do not need to be grouped. Because everyone is of a gender
9s-5s=4s
4s+2s=6s
6s-s=5s
answer: 5s

E) 8t+3r-7t-9r=
Group the same sexes
8t-7t+3r-9r=
8t-7t=t
+3r-9r=-3r
answer: t-3r

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levacccp [35]

To solve this problem you can do a proportion
$\frac{x}{215} = \frac{35\%}{100\%}$
to find 'x', we have to cross multiply the numbers.
$215 \times 35$
and
$100 \times x$
this will get you
$7525 = 100x$
to get 'x', we have to divide by 100 on each side
$\frac{7525}{100} = \frac{100x}{100}$

your answer will be
$75.25 = x$
so, Chris must raise 75.25 dollars by himself

3 0

2 years ago

Please explain how to do this one as well ...

kirza4 [7]

Answer:

x = 13

Step-by-step explanation:

Step 1: Define

f(x) = (x - 1)/2

f(x) = 6

Step 2: Substitute and solve for x

6 = (x - 1)/2

12 = x - 1

x = 13

4 0

3 years ago

the area of a rectangular field is x^2-x-72 m^2. The length of the field is x+8 cm. What is the width of the field meters.

Gre4nikov [31]

Hello,

A(x)=x²-x-72 (m²)
L=(x+8) (cm)= (x+8)/100 (m)

We suppose here x≠-8
(in reality x²-x-72>0 ==>x<-8 or x>9
but x+8>0 ==> x>-8
then
only x>9 are solutions)

W=A(x)/ ((x+8)/100 )=100*(x²-x-72)/(x+8)= 100*(x-9)(x+8)/(x+8)=100*(x-9)

5 0

2 years ago

The area of the above polygon is ? the answer is not 44

vitfil [10]

Check the picture below.

you really have two rectangles, a 6x10 and a 6x5, and surely you know what those areas are, so sum them up, and that's the area of the polygon.

6 0

3 years ago

Can someone help on both of the questions, i dont get it

o-na [289]

Answer:

A. finished 1km

Step-by-step explanation:

b. 8km per hour

6 0

2 years ago