Lucy did an experiment. She started out with 500 bacteria cells. She found that the growth rate of the bacteria cells was 4.7%.
1 answer:
An equation that represents the population of the bacteria at time x is y = 500(1.047)^x.
<h3>What is the equation?</h3>The bacteria grows at an exponential rate. An exponential growth rate means that the growth rate of the bacteria would increase overtime.
The general form of exponential equation is f(x) =
Where:
- x = the variable
- e = constant
The future population of the bacteria can be represented with:
FV = P(1 + r)^x
Where:
- FV= future bacteria population
- r = rate of growth
- P = present bacteria population
- x = number of years
y = 500(1 + 0.047)^x
y = 500(1.047)^x.
To learn more about exponential functions, please check: brainly.com/question/26331578
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<u>Given</u>:
Given that the irregular figure is broken into a triangle and a rectangle.
We need to determine the length b, the area of the triangle , the area of the rectangle and the area of the irregular figure.
<u>Length of b:</u>
The length of b , the base of the triangle is given by
Simplifying, we get;
Thus, the length of the base of the triangle is
<u>Area of the triangle:</u>
The area of the triangle can be determined using the formula,
Substituting and
, we get;
Thus, the area of the triangle is 4 square feet.
<u>Area of the rectangle:</u>
The area of the rectangle can be determined using the formula,
where l = 5 ft, , we get;
Thus, the area of the rectangle is
<u>Area of the irregular figure:</u>
The area of the irregular figure can be determined by adding the area of the triangle and the area of the rectangle.
Thus, we have;
Area = Area of the triangle + Area of the rectangle
Substituting the values, we have;
Thus, the area of the irregular figure is 10.667 square feet.
We know that there are 100 cm in 1 m. We can convert 0.75 m to cm by multiplying by 100 to give us:
Therefore the path before the addition is 75 cm wide.
Mr. Kassel added 20 cm of blocks on each side of the path, meaning that the added width is actually 40 cm total (20 on each side, and there are 2 sides).
So we need to add 40 cm to the original 75 cm:
So now we have the width of the path in cm, the question asks for the width in meters. We can do this by dividing the width in cm by 100 to get the width in meters:
Now we know that the new width of the path is 1.15 m.
Therefore the path before the addition is 75 cm wide.
Mr. Kassel added 20 cm of blocks on each side of the path, meaning that the added width is actually 40 cm total (20 on each side, and there are 2 sides).
So we need to add 40 cm to the original 75 cm:
So now we have the width of the path in cm, the question asks for the width in meters. We can do this by dividing the width in cm by 100 to get the width in meters:
Now we know that the new width of the path is 1.15 m.