Answer:
Step-by-step explanation:
When solving equations with fractional or decimal coefficients, the equations needs to be multiplied by the multiple of denominator such that the equations have integer coefficients and constants
Before jumping into doing this problem, it is important to look at all the information's that have been made available in the question. Based on those given conditions the answer to the problem can be easily deduced.
Let us assume the number of friends Sumalee has = x
Then
2x + 8 = 40
2x = 40 -8
2x = 32
x = 32/2
x = 16
So Sumalee has 16 friends. There are numerous ways to get to the answer that is required to be found. This is the easiest and the shortest method. Hope i helped you.
Answer:
53/100
Step-by-step explanation:
First, we convert the fraction to a decimal number by dividing the numerator by the denominator:
8 / 15 = 0.533
There are two parts to the decimal number above:
Integer Part: 0
Fractional Part: 533
Now, we will make the Fractional Part just two digits (nearest hundredth) by using our rounding rules.*
In this case, Rule I applies, so 8/15 (or 0.533) rounded to the nearest hundredth in decimal format is:
0.53
Next, we will make 8/15 rounded to the nearest hundredth in fraction format. Since you can divide our decimal format answer above by 1 and keep the same value, you can make it like this:
0.53 = 0.53/1
Then, we multiply the numerator and denominator by 100 to get rid of the decimal point:
(0.53 x 100) / (1 x 100) = 53/100
That's it. 8/15 rounded to the nearest hundredth is displayed below (simplified if necessary):
53/100
Answer:
yp = -x/8
Step-by-step explanation:
Given the differential equation: y′′−8y′=7x+1,
The solution of the DE will be the sum of the complementary solution (yc) and the particular integral (yp)
First we will calculate the complimentary solution by solving the homogenous part of the DE first i.e by equating the DE to zero and solving to have;
y′′−8y′=0
The auxiliary equation will give us;
m²-8m = 0
m(m-8) = 0
m = 0 and m-8 = 0
m1 = 0 and m2 = 8
Since the value of the roots are real and different, the complementary solution (yc) will give us
yc = Ae^m1x + Be^m2x
yc = Ae^0+Be^8x
yc = A+Be^8x
To get yp we will differentiate yc twice and substitute the answers into the original DE
yp = Ax+B (using the method of undetermined coefficients
y'p = A
y"p = 0
Substituting the differentials into the general DE to get the constants we have;
0-8A = 7x+1
Comparing coefficients
-8A = 1
A = -1/8
B = 0
yp = -1/8x+0
yp = -x/8 (particular integral)
y = yc+yp
y = A+Be^8x-x/8