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kipiarov [429]
1 year ago
10

which periodic trend quantifies the amount of energy required to remove an electron from a neutral, gaseous atom? a) atomic radi

us b) ionization energy c) ionic radius d) electron affinity e) electronegativity
Chemistry
1 answer:
ahrayia [7]1 year ago
5 0

Ionization energy is the energy needed to remove one electron from an atom in the gaseous state.

Ionization energy (IE) is the force needed to ionize a neutral atom or cation when it is in its gaseous state. Ionization potential is another name for IE. Ionization energy is conceptually defined as an element's affinity for its outermost electron (an electron it already has in its valence shell).

The least amount of energy needed to ionize an atom is needed to remove an electron from its ground state. Across the periodic table, there is a regular increase in ionization energy from top to bottom and left to right.

To learn more about Ionization energy visit:brainly.com/question/28385102

#SPJ4

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SHOW YOUR WORK!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
WARRIOR [948]

Answer:

1.375%

Explanation:

Percent Error = measured value - accepted value/ accepted value x 100

Measured Value: 15.78

Accepted Value: 16.00

Work:

\frac{15.78-16.00}{16.00} * 100

\frac{-.22}{16} * 100 = -1.375

You cannot have a negative percentage. Therefore the answer is 1.375%

4 0
3 years ago
_: brings food and water to your cells.
Rama09 [41]

Answer:

Mitochondria brings food and water to your cells

4 0
3 years ago
Write in which of these processes heat is absorbed or releases heat.
neonofarm [45]

Answer:

1. Endothermic process

4Exothemic process

3 0
2 years ago
Copper can have improved wear resistance if alloyed with ceramic alumina, Al2O3. If a copper alloy has 7.7 wt % Al2O3, what is i
vitfil [10]

The composition in mol% of the elements are :

  • 4.91%  of Al₂O₃ in alloy  
  • 95.08% of Cu in alloy

<u>Given data : </u>

Weight percentage of copper alloy = 7.7 wt %

Assume weight of alloy = 100 grams

<h3>Applying the weight percentage </h3>

mass of Al₂O₃ in alloy = 7.7 gm

Mass of Cu in alloy = 100 - 7.7 = 92.3 gm

<u />

<u>First step : calculate the mole of elements</u>

i) moles of Al₂O₃ in alloy

 = mass of Al₂O₃  in alloy /  Atomic mass of Al₂O₃

 = 7.7 gm  / 102 gm/mol

 = 0.075 mol

ii) moles of Cu in alloy

 = mass of Cu in alloy / Atomic mass of Cu

 = 92.3 gm / 63.5 gm/mol

 = 1.45 mol

Therefore the total number of moles in the alloy = 0.075 + 1.45 = 1.525

<u>Next step : Determine the mole </u><u>percentages </u>

i) Mole percentage of Al₂O₃ in alloy  

= ( 0.075 ) / 1.525  * 100

= 4.91%

ii) Mole percentage of Cu in alloy

= ( 1.45 ) / 1.525 * 100

= 95.08%

<u />

Hence we can conclude that The composition in mol% of the elements are : 4.91%  of Al₂O₃ in alloy and  95.08% of Cu in alloy.

Learn more about alloys : brainly.com/question/716507

4 0
2 years ago
What powers explosions and fire?
docker41 [41]

Answer:

Oxygen

Explanation:

I'm not completely sure about the explosion part but I know oxygen fuels fire.

4 0
3 years ago
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