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kotegsom [21]
3 years ago
6

Which is the best description of a cyclone?

Chemistry
1 answer:
RoseWind [281]3 years ago
4 0
I think the one that best describes a cyclone is the first one (a dust storm rapidly changing weather in an area)
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How many parts per million of fluoride in a solution that is 500 grams of fluoride and 500,000 liters water
erik [133]

0.000001‬ppm

Explanation:

Mass of fluoride = 500g

Volume of water = 500000liters

Unknown:

Parts per million of fluoride = ?

Solution:

The parts per million is the amount of solute in milligram dissolved in a liter of water or milligram per kilogram of solvent

It is a unit used to express very small concentration.

 we need to convert g - mg

   500g = 500 x  10⁻³mg  = 0.5mg

   Concentration in parts per million = \frac{mass in mg}{Volume in liters}

Concentration in parts per million = \frac{0.5}{500000} = 0.000001‬ppm

learn more:

Parts per million brainly.com/question/2854033

#learnwithBrainly

7 0
3 years ago
Two atoms of calcium and one molecule of oxygen gas react and yield two molecules of calcium oxide.
Vitek1552 [10]
2Ca + O2 ——————-> 2CaO2
3 0
3 years ago
Which side does the light always start from?
jarptica [38.1K]

Answer:

in prism

it's from the rectangular reflecting surface

7 0
2 years ago
Does anyone have geometry on edg ??!!!
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2 years ago
A sample of an unknown gas takes 371 s to diffuse through a porous plug at a given temperature.
blsea [12.9K]

Answer:

125.84 g/mol is the molar mass of the unknown gas.

Explanation:

Let the volume of the gases effusing out be V.

Effusion rate of the unknown gas = R=\frac{V}{371 s}

Effusion rate of the nitrogen gas = r=\frac{V}{175 s}

Molar mass of unknown gas = m

Mass of nitrogen gas = 28 g/mol

Graham's law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

\frac{R}{r}=\sqrt{\frac{28 g/mol}{M}}

\frac{\frac{V}{371 s}}{\frac{V}{175s}}=\sqrt{\frac{28 g/mol}{M}}

\frac{175 s}{371 s}=\sqrt{\frac{28 g/mol}{M}}

M=\frac{28 g/mol\times 371\times 371}{175\times 175}=125.84 g/mol

125.84 g/mol is the molar mass of the unknown gas.

5 0
3 years ago
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