The answer is B.) I took the test.
Answer:
The edge length is 0.4036 nm
Solution:
As per the question:
Density of Ag, 
Density of Pd, 
Atomic weight of Ag, A = 107.87 g/mol
Atomic weight of Pd, A' = 106.4 g/mol
Now,
The average density, 
where
= Volume of crystal lattice
a = edge length
n = 4 = no. of atoms in FCC
Therefore,

Therefore, the length of the unit cell is given as:
(1)
Average atomic weight is given as:

where
= 79 %
= 107
= 21%
= 106
Therefore,

In the similar way, average density is given as:


Therefore, edge length is given by eqn (1) as:

Answer:
120N
Explanation:
Newton's second law formula: F= ma
given that m = 10 kg, a = 12 m/s^2
F = ma = 10 kg * 12 m/s^2 = 120 kgm/s^2 = 120 N
Answer:
(a) The initial speed required is 13116 m/s
(b) The escape speed is 10394 m/s
This problem involves the application of newtons laws of gravitation. The forces in action here are conservative and as a result mechanical energy is conserved.
The full calculation can be found in the attachment below.
Explanation:
In both parts (a) and (b) the energy conservation equation were used. Assumption was made that when the object is very far from the planet the distance from the planet's center approaches infinity and the gravitational potential energy approaches zero.
The calculation can be found below.
Speed = Distance/ Time
Speed = 400 / 4
Speed = 100 km/hr.
100 km per hour.