Answer:
The fractional kinetic energy will be lost if the collision is inelastic. In inelastic collision, the kinetic energy is converted into other forms of energy.
The lost energy became heat and sound energy.
Explanation:
During inelastic collision, the kinetic energy of a moving object does not conserve. It changes into another form of energy such as sound energy and heat energy etc.
For example, when a moving car hit another car or wall etc, the kinetic energy is converted into sound and heat energy. This type of collision is inelastic collision.
Answer:
(a) T = 10 s
(b) f = 0.1 Hz
(c) λ = 32 m
(d) v = 3.2 m/s
(e) Insufficient data
Explanation:
(a)
Time period is defined as the time interval required for one wave to pass. Therefore, the time period can be given as:
T = Period = Time Taken/No. of Waves
T = 50 s/5
<u>T = 10 s</u>
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(b)
Frequency is the reciprocal of time period:
f = frequency = 1/T
f = 1/10 s
<u>f = 0.1 Hz</u>
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(c)
Wavelength is the distance between two consecutive crests or troughs:
<u>λ = Wavelength = 32 m</u>
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(d)
Speed of wave is given by the following formula:
Speed = v = fλ
v = (0.1 Hz)(32 m)
v = 3.2 m/s
(e)
Amplitude cannot be found with given data.
The statement above is FALSE.
The right hand rule is used in physics to predict the direction of the force on a charged object moving in a MAGNETIC FIELD. The right hand rule is used to relate the relationship between the magnetic field and the forces that are exerted on the moving objects in the field. Using the right hand rule, for a positively charged object that is moving in an electric field, the pointer finger will point in the direction the charged object is moving, the middle finger will point in the direction of the magnetic field and the thumb will point in the direction of the magnetic force that is pushing the charged object.
Pressure is the force applied perpendicular to the surface of an object per unit area over which that force is distributed.
P=F/A
Answer:
A = 4.6 [m²]
Explanation:
The area of a circle can be calculated by means of the following equation.
where:
A = area [m²]
D = diameter = 2.42 [m]
Now replacing:
![A=\frac{\pi }{4} *(2.42)^{2} \\A = 4.6 [m^{2} ]](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B%5Cpi%20%7D%7B4%7D%20%2A%282.42%29%5E%7B2%7D%20%5C%5CA%20%3D%204.6%20%5Bm%5E%7B2%7D%20%5D)
