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3 years ago

WORTH 50 POINTS!!! Please help me with questions 1,2,3,4,5,6 and 7 ASAP!

Physics

1 answer:

boyakko [2]3 years ago

6 0

This is a good example of unit conversion. Look at the units you have and the units you need to solve for.

In #1 you’re given weight in units N and area in units cm². You want to find pressure in units Pa (pascals) which is force/area, or N/m². So you just divide the force given by the area given, but be careful because the area is given in cm², whereas pressure is in m². Before you calculate pressure, make sure you convert 324cm² into m²

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You find it takes 200 N of horizontal force tomove an unloaded pickup truck along a level road at a speed of2.4 m/s. You then lo

IgorC [24]

ANSWER:

F(h)= 230 N is the horizontal force you will need to move the pickup along the same road at the same speed.

STEP-BY-STEP EXPLANATION:

F(h) is Horizontal Force = 200 N

V is Speed = 2.4 m/s

The total weight increase by 42%

coefficient of rolling friction decrease by 19%

Since the velocity is constant so acceleration is zero; a=0

Now the horizontal force required to move the pickup is equal to the frictional force.

F(h) = F(f)

F(h) = mg* u

m is mass

g is gravitational acceleration = 9.8 m/s^2

200 = mg*u

Since weight increases by 42% and friction coefficient decreases by 19%

New weight = 1+0.42 = 1.42 = (1.42*m*g)

New friction coefficient = μ = 1 - 0.19 = 0.81 = 0.81 u

F(h) = (0.81μ) (1.42 m g)

= (0.81) (1.42) (μ m g)

= (0.81) (1.42) (200)

= 230 N

4 0

3 years ago

Which of the following statements is untrue in regard to sound traveling in air?

maksim [4K]

Air never stops? IDK

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Leni [432]

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Elanso [62]

Answer:

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Explanation:

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Hope that was helpful.Thank you!!!

3 0

3 years ago

Read 2 more answers

Find the length of a pendulum that oscillates with a frequency of 0.16 hz. the acceleration due to gravity is 9.81 m/s 2 . answe

Vsevolod [243]

The period of the pendulum is the reciprocal of the frequency:
$T= \frac{1}{f}= \frac{1}{0.16 Hz}=6.25 s$

The period of the pendulum is given by
$T=2 \pi \frac{L}{g}$
where L is the length of the pendulum, and g the acceleration of gravity. By re-arranging the formula and using the value of T we found before, we can calculate the length of the pendulum L:
$L=g \frac{T^2}{(2 \pi)^2}=(9.81 m/s^2) \frac{(6.25 s)^2}{(2 \pi)^2}=9.71 m$

7 0

3 years ago