Ask question

Ask question

All categories

3 years ago

7

A mosquito flying over a highway strikes a windshield of a moving truck. Compared to the magnitude of the force of the truck on

the mosquito during collision, the magnitude of the force of the mosquito on the truck is
Larger
Smaller
The Same
Cant be determined

1 answer:

krok68 [10]3 years ago

3 0

Answer:

the answer to this question is

<em>The</em><em> </em><em>Same</em><em> </em>

<em>newton's</em><em> </em><em>law</em><em> </em><em>#3</em>

Explanation:

<em>Hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em>

You might be interested in

Calculate the moment of inertia for each scenario: (a) An 80.0 kg skater is approximated as a cylinder with a 0.140 m radius. (b

Zina [86]

Answer:

a) the moment of inertia is 0.784 Kg*m²

b) the moment of inertia is with arms extended is 1.187 Kg*m²

c) the angular velocity in scenario (b) is 4.45 rad/s

Explanation:

The moment of inertia is calculated as

I = ∫ r² dm

since

I = Ix + Iy

and since the cylinder rotates around the y-axis then Iy=0 and

I = Ix = ∫ x² dm

if we assume the cylinder has constant density then

m = ρ * V = ρ * π R²*L = ρ * π x²*L

therefore

dm = 2ρπL* x dx

and

I = ∫ x² dm = ∫ x² 2ρπL* x dx = 2ρπL∫ x³ dx = 2ρπL (R⁴/4 - 0⁴/4) = ρπL R⁴ /2 = mR² /2

therefore

I skater = mR² /2 = 80 Kg * (0.140m)²/2 = 0.784 Kg*m²

b) since the arms can be seen as a thin rod

m = ρ * V = ρ * π R²*L = ρ * π R²*x

dm =ρ * π R² dx

I1 = ∫ x² dm = ∫ x² * ρ * π R² dx = ρ * π R²*∫ x² dx = ρ * π R²* ((L/2)³/3 - (-L/2)³/3)

= ρ * π R²*2*L³/24 = mL²/12

therefore

I skater 2 = I1 + I skater = mL²/12 + mR² /2= 8 Kg* (0.85m)²/12 +(80-8) Kg * (0.140m)²/2 = 1.187 Kg*m²

c) from angular momentum conservation

I s2 * ω s2 = I s1 * ω s1

thus

ω s2 = (I s1 / I s2 )* ω s1 /= (0.784 Kg*m²/1.187 Kg*m²) * 6.75 rad/s = 4.45 rad/s

4 0

2 years ago

In any energy transformation, there is always some energy that gets wasted as non-useful heat. True or False.

Mila [183]

This is true all the time

7 0

3 years ago

Read 2 more answers

You hike two thirds of the way to the top of a hill at a speed of 2.9 mi/h and run the final third at a speed of 5.6 mi/h. What

Marta_Voda [28]

Answer:

The average speed is 3.5 mi/h

Explanation:

Average speed is given by

$Average speed = \frac{Total distance}{Total time}$

If the total distance covered is $x$ mi,

Then $\frac{2}{3}x$ mi was covered while hiking and

$\frac{1}{3}x$ mi was covered while running.

Now, we will find the time taken while hiking and the time taken while running

$Speed = \frac{Distance}{ Time}\\ Time = \frac{Distance}{Speed}$

For the time taken while hiking

Speed = 2.9 mi/h

Distance = $\frac{2}{3}x$ mi

From,

$Time = \frac{Distance}{Speed}$

$Time = \frac{\frac{2}{3}x }{2.9}$

Time = $0.2299x$ h

Time taken while hiking is 0.2299 h

For the time taken while running

Speed = 5.6 mi/h

Distance = $\frac{1}{3}x$ mi

$Time = \frac{Distance}{Speed}$

$Time = \frac{\frac{1}{3}x }{5.6}$

Time = $0.05952x$ h

Now, for the average speed

$Average speed = \frac{Total distance}{Total time}$

Total distance = $\frac{2}{3}x$ mi + $\frac{1}{3}x$ mi = $x$ mi

Total time = $0.2299x$ + $0.05952x$ = $0.28942x$ h

∴ $Average speed = \frac{x}{0.28942x}$

Average speed = 3.4552 mi/h

Average speed ≅ 3.5 mi/h

3 0

3 years ago

What were the three topographical climate factors we talked about?

tigry1 [53]

Answer:

Dry Arid, Coastal, Mountains

Explanation:

Took the text

5 0

3 years ago

2. If, in the previous question, there is a 15 N kinetic frictional force opposing the motion, how much work is

NeTakaya

Answer:

this answer your question

4 0

2 years ago