Ask question

Ask question

All categories

3 years ago

7

A mosquito flying over a highway strikes a windshield of a moving truck. Compared to the magnitude of the force of the truck on

the mosquito during collision, the magnitude of the force of the mosquito on the truck is
Larger
Smaller
The Same
Cant be determined

1 answer:

krok68 [10]3 years ago

3 0

Answer:

the answer to this question is

<em>The</em><em> </em><em>Same</em><em> </em>

<em>newton's</em><em> </em><em>law</em><em> </em><em>#3</em>

Explanation:

<em>Hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em>

You might be interested in

Susan is making an electromagnet in her science class today. First, she takes a nail and winds coils of copper wire around it th

matrenka [14]

Answer:

Electrical

Explanation:

She uses a battery, which is electrical.

It doesn't operate using chemicals, heat, or light

5 0

3 years ago

Read 2 more answers

An automobile with an initial speed of 4.92 m/s accelerates uniformly at the rate of 3.2 m/s2 . Find the final speed of the car

Rudik [331]

Answer:19.32 m/s

Explanation:

Given

initial speed of car(u)=4.92 m/s

acceleration(a)= $3.2 m/s^2$

Speed of car after 4.5 s

using equation of motion

v=u+at

$v=4.92+3.2\times 4.5=4.92+14.4$

v=19.32 m/s

Displacement of the car after 4.5 s

$v^2-u^2=2as$

$19.32^2-4.92^2=2\times 3.2\times s$

$349.05=2\times 3.2\times s$

s=54.54 m

4 0

2 years ago

An irregular object of mass 3 kg rotates about an axis, about which it has a radius of gyration of 0.2 m, with an angular accele

Citrus2011 [14]

Answer:

The magnitude of the applied torque is $6.0\times10^{-2}\ N-m$

(e) is correct option.

Explanation:

Given that,

Mass of object = 3 kg

Radius of gyration = 0.2 m

Angular acceleration = 0.5 rad/s²

We need to calculate the applied torque

Using formula of torque

$\tau=I\times\alpha$

Here, I = mk²

$\tau=mk^2\times\alpha$

Put the value into the formula

$\tau=3\times(0.2)^2\times0.5$

$\tau=0.06\ N-m$

$\tau=6.0\times10^{-2}\ N-m$

Hence, The magnitude of the applied torque is $6.0\times10^{-2}\ N-m$

7 0

3 years ago

In February 1955, a paratrooper fell 365 m from an airplane without being able to open his chute but happened to land in snow, s

DaniilM [7]

Answer:

a. $i=4760 kg*m/s$

b. $D_U= 1.11 m$

Explanation:

a)

F= 120,000N

Kinetic energy @ impact = 120,000*depth

$K_E= (1/2)*85kg*(56m/s)^2$

$K_E=133280 J$

$D_U= \frac{133280J}{120000N} = 1.11 m$

b)

The momentum is equal to the impulse on him from the snow so:

$p=m*v$

$p=85kg*56m/s$

$i=4760 kg*m/s$

7 0

3 years ago

Why is an earthworm an invertebrate?

zimovet [89]

Earthworm have bones Some children confuse earthworms, which are invertebrates and have no bones, with snakes which are vertebrates and do have a bony skeleton and many ribs.

8 0

3 years ago

Read 2 more answers