When ultraviolet light with a wavelength of 400 nm falls on a certain metal surface, the maximum kinetic energy of the emitted photoelectrons is 1.10 eV.
What is the maximum kinetic energy Ko of the photoelectrons when light of wavelength 350 nm falls on the same surface?
Use h= 6.63×10-34 J * s for Planck's constant and c= 3.00×10^8 m/s for the speed of light and express your answer in electron volts.
Answer with Explanation:
We are given that
Charge on proton,q=
a.We have to find the electric potential of the proton at the position of the electron.
We know that the electric potential
Where 
B.Potential energy of electron,U=
Where
Charge on electron
=Charge on proton
Using the formula
Density=mass/volume therefore volume=mass/density; 55g/11.4g/cm^3= 4.82cm^3
