Answer:
36 volts
If the circuit has a current of 3 amps, and a 12 ohm resistor.
12 x 3 = 36volts
Answer:
The magnetic field strength is 3.9 x 10⁻³ T
Explanation:
The equation for the magnetic field strength produced by a long straight current-carrying wire is written as;

Where;
μ₀ is constant = 4π x 10⁻⁷ N/A
I is the maximum current = 20 A
r is the radius of the wire = 2.053/2 = 1.0265 mm = 1.0265 x 10⁻³ m
Substitute in this values into the equation above;

Therefore, the magnetic field strength is 3.9 x 10⁻³ T
The closer the particles, the more will be the propogation of sound waves. Room contains air molecules which are far away from each other. So it takes much time for one molecule of air to disturb the other one. But in case of solids, as particles are much closer(compared to fluids), disturbance generated by one molecule is quickly transmitted to the next molecule
Answer:
The kinetic energy of the phone would increase. The gravitational potential energy of the phone would decrease.
Explanation:
The kinetic energy
of an object is proportional to the square of the speed of that object. If air resistance is negligible, the phone would accelerate under gravitational pull and speed up. Hence, the kinetic energy of the phone would increase.
The gravitational field near the surface of the earth is approximately constant. Hence, the gravitational potential energy
of the phone would be proportional to its height. As the phone approaches the ground, the height of the phone becomes lower and the gravitational potential energy of the phone would decrease.