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Anna007 [38]
2 years ago
11

A 10kg box accelerates forward at a rate of 12 m/s^2. What is the force acting on the box?

Physics
1 answer:
Allushta [10]2 years ago
5 0

Answer:

120N

Explanation:

Newton's second law formula: F= ma

given that m = 10 kg, a = 12 m/s^2

F = ma = 10 kg * 12 m/s^2 = 120 kgm/s^2 = 120 N

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La altura de un tornillo de banco respecto a la superficie es de 80 cm expresar dicha medida en pies..
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Answer:

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Explanation:

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3 years ago
A firecracker in a coconut blows the coconut into three pieces. Twopieces of equal mass fly off south and west, perpendicular to
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Answer:

V = 13m/s

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We have

V_{y} = Velocity in South direction = 18m/s

m_{y} = Mass of piece in South direction = m

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m_{x} = Mass of piece in West direction = m

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m = Mass of third piece = 2m

mV_{ry}  = m_{y} V_{y} \\ 2mV_{ry}  = m18\\ V_{ry} = 9

mV_{rx}  = m_{x} V_{x} \\ 2mV_{rx}  = m18\\ V_{rx} = 9

Since we now know the horizontal and vertical component of the velocity of the third piece of coconut we find the resultant velocity. Since we know the direction is North-East, we can imagine a right angled triangle with base of 9 and height 9 and the hypotenuse equal to the resultant velocity .

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V = 13m/s

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