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2 years ago

A 10kg box accelerates forward at a rate of 12 m/s^2. What is the force acting on the box?

Physics

1 answer:

Allushta [10]2 years ago

5 0

Answer:

120N

Explanation:

Newton's second law formula: F= ma

given that m = 10 kg, a = 12 m/s^2

F = ma = 10 kg * 12 m/s^2 = 120 kgm/s^2 = 120 N

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Answer:

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K1 +U1 = K2 +U2

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3 years ago

Which of the following is the best explanation for acceleration? *

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3 years ago

A sled of mass 2.12 kg has an initial speed of 5.49 m/s across a horizontal surface. The coefficient of kinetic friction between

Darya [45]

Answer:

The speed of the sled is 3.56 m/s

Explanation:

Given that,

Mass = 2.12 kg

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Where, F = frictional force

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$a=\dfrac{\mu mg}{m}$

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Using equation of motion

$v^2=u^2-2as$

Where, v = final velocity

u = initial velocity

a = acceleration

s = distance

Put the value in the equation

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$v=\sqrt{(5.49)^2-2\times2.244\times3.89}$

$v=3.56\ m/s$

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