Question

---!99 POINTS!---

Answer 1

Its a square with 3 right triangles,
6*6+1/2(6+12+18)
=36+1/2(36)
=36+18
=54

Answer 2

You can split this figure into two parts:

1. Triangle ABF with base $|BF|=10$ and height $|AE|=3$
Area of that triangle is:

$A_\Delta=\dfrac{1}{2}\cdot|BF|\cdot|AE|=\dfrac{1}{2}\cdot10\cdot3=5\cdot3=\boxed{15}$

2. Trapezoid BCDE with bases $|CD|=7$ and $|EB|=6$ and with height $|BC|=6$. Its area:

$A_T=\dfrac{|CD|+|EB|}{2}\cdot|BC|=\dfrac{7+6}{2}\cdot6=\dfrac{13}{2}\cdot6=13\cdot3=\boxed{39}$

So area of the shape is:

$A=A_\Delta+A_T=15+39=\boxed{54\text{ units}^2}$