Answer:
0, for q ≠ 0 and q ≠ 1
Step-by-step explanation:
Assuming q ≠ 0, you want to find the value of x such that ...
q^x = 1
This is solved using logarithms.
__
x·log(q) = log(1) = 0
The zero product rule tells us this will have two solutions:
x = 0
log(q) = 0 ⇒ q = 1
If q is not 0 or 1, then its value is 1 when raised to the 0 power. If q is 1, then its value will be 1 when raised to <em>any</em> power.
_____
<em>Additional comment</em>
The applicable rule of logarithms is ...
log(a^b) = b·log(a)
Answer:
Step-by-step explanation:
Calculate for the value of 
:
-Use <u>Distributive Property</u> on both left and right:
-Take 
and subtract 
:
-Add 
to both sides:
-Take 
and divide on both sides:
Therefore, the value of is 
.
x² + 7x - 4 = 0
a = 1, b = 7, c = -4
x = [-b +/- √(b² - 4ac)]/2a
= [-7 +/- √(49 + 4)]/2
= (-7 +/- √53)/2
