Answer:
9.01 grams
Explanation:
~18.02 grams are in 1 mole of water so you'd divide that in half to get 9.01 grams.
Answer:
When a gas occupies a smaller volume, it exerts a higher pressure; when it occupies a larger volume, it exerts a lower pressure (assuming the amount of gas and the temperature do not change). Since P and V are inversely proportional, a graph of 1/P vs. V is linear.
Explanation:
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The entropy of a system can be calculated by the ratio of the total heat in the system and the temperature. Entropy is a measure used in thermodynamics to approximate the degree of disorder in a system. From the equation for entropy, we can calculate the enthalpy as follows:
S = H / T
109.0 J / mol K = H / 373.15 K
H = 40673.35 J / mol
Concentration of vinegar sample of 28mL which requires 21. 5 ml of 0.550 M NaOH to reach the endpoint in a titration is 0.42M.
<h3>How do we calculate the concentration of Vinegar?</h3>
Concentration of vinegar in the titration method will be used by using the below equation:
M₁V₁ = M₂V₂,
- M₁ & V₁ are the molarity and volume of acetic acid.
- M₂ & V₂ are the molarity and volume of vinegar sample.
By putting values on above equation from the question, we get
M₂ = (0.55M)(21.5mL) / (28mL) = 0.42 M
Hence, required concentration of vinegar is 0.42M.
To know more about concentration, visit the below link:
brainly.com/question/14469428
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