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1 answer:
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Answer:
12,5.196
Step-by-step explanation:
given that the radius of a circle is 6.
We have any tangent drawn from outside point there will be two tangents of equal length and also the line joining point of intersection of tangent with centre of circle will bisect the angle between the tangents.
When angle between the two tangents is 60, we have the right triangle formed by radius, one tangent, and line joining point of intersection of tangent with centre of circle with angles 30,60 and 90
Hence the hypotenuse = length of line segment of tangent = 2 (radius) = 12
Part 2:
When angle between tangents is 120, we have 60,30,90 right triangle and hence length of tangent = radius * sin 60
=
Perimeter of triangle ABC is 20 units.
Solution:
The image for reference is attached below.
Given AE = 2, BD = 5 and CF = 3
Two tangents drawn from an external point to a circle are equal in length.
AD = AE, BF = BD and CE = CF
Therefore, AD = 2, BF = 5 and CE = 3
Perimeter of the triangle = sum of the three sides
Perimeter of triangle ABC = AB + BC + CA
= AD + BD + BF + CF + CE + AE
= 2 + 5 + 5 + 3 + 3 + 2
= 20
Hence, perimeter of triangle ABC is 20 units.
