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3 years ago

Help! picture attached

Mathematics

1 answer:

konstantin123 [22]3 years ago

4 0

You need to turn 1/2 to .5 and 3/4 to .75 then you use this equation.
75% * 950,000 (profit)
+ 25% * -285,000 (loss)
= then you subtract the numbers from the separate 
= answer --> expected profit from the second mall

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Express a(2) (2a(-1/2)+a) in its simplest form

Soloha48 [4]

First lets simplify the first term and yield (2a)

The second term:
1. 2a * (-1/2) = -a
2. -a + a = 0

Now we have simplified both terms to: (2a) (0)

Anything multiplied by 0 is 0, so the answer is also 0.

4 0

3 years ago

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Please help will give brainlist

adoni [48]

Answer:

It would be option 2.

Step-by-step explanation:

This is because option 1 does not have a irrational number that goes on indefinitely, option three has the square root of 25, which equals 5 meaning it is rational, and the last option also gives us rational choices. Therefore, the only possibility is that it would be option 2.

6 0

3 years ago

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HELP! <img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx-1%7D-x%3D-7" id="TexFormula1" title="\sqrt{x-1}-x=-7" alt="\sqrt{x-1}-x=

katen-ka-za [31]

$\huge \huge \huge\huge\mathrm{ \boxed{ \boxed{ \boxed{ \boxed{ \boxed {\boxed{ \huge\mathfrak{ Solution}}}}}}}}$

$\sqrt{x - 1} - x = - 7$

$\sqrt{x - 1} =x - 7$

$x - 1 = (x - 7) {}^{2}$

$x - 1 = {x}^{2} + 49 - 14x$

${x}^{2} - 14x + 49 - x + 1 = 0$

${x}^{2} - 15x + 50 = 0$

${x}^{2} - 10x - 5x + 50 = 0$

$x(x - 10) - 5(x - 10) = 0$

$(x - 5)(x - 10) = 0$

$x = 5 \: \: \: or \: \: \: x = 10$

6 0

2 years ago

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Four less than five times a number is equal to 11

hjlf

5x-4=11 is the equation you are referring to.

7 0

3 years ago

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Complete each statement in the steps to solve x2 – 6x – 7 = 0 using the process of completing the square. Isolate the constant b

Tomtit [17]

"Isolate the constant by adding 7 to both sides of the equation."
This step separates the non-squareable 7 and the squareable $x^2 - 6x$ .

"Add 9 to both sides of $x^2 - 6x = 7$ to form a perfect square trinomial while keeping the equation balanced."
After separating the non-squareable, add the number which makes the first or left side a perfect square trinomial. The formula to find the number is: $c = {\frac{b}{2} }^{2}$ .
When we plug the values: $c = { \frac{ - 6}{2} }^{2}$
Simplify: $c = {( - 3)}^{2} = 9$

"Write the trinomial $x^2 - 6x + 9$ as $(x - 3)$ squared."
When you factor $x^2 - 6x + 9$ , you will get $(x - 3) \times (x - 3)$ .

"Use the square root property of equality to get $x - 3 = ± \sqrt{16}$ ."
The 16 is coming from the part when we add 9. We needed 9 on the left side for a perfect square, but to protect the balance of the equality, we need to add 9 to the right side too. When we add 7 and 9, we got 16, and that is where it came from.

"Isolate the variable x to get solutions of -1 and 7."
To isolate x we branched the plus-minus sign:
$x - 3 = 4 \: \: \: x = 4 + 3 = 7 \\ \\ x - 3 = - 4 \: \: \: x = - 4 + 3 = - 1$

8 0

2 years ago

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