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Maru [420]
1 year ago
5

The notation __1____ reads the probability of Event B given that Event A has occurred. If Events A and B are independent, then t

he probability of Event A occurring ___2___the probability of Event B occurring. Events A and B are independent if_3____1.A. P(AlB)B. P(BlA)C. P (A and B)2. A. Doesn't affectB. Affects3. A. P(BIA) = P(B)B. P(BIA) = P(A)C. P (BIA)= P(A and B).
Mathematics
1 answer:
telo118 [61]1 year ago
3 0

P(B|A) (option B)

Doesn't affect (option A)

P(B|A) = P(B) (option A)

Explanation:

1) Conditional probabilities could be in the form P(A|B) or P(B|A)

P(B|A) is a notation that reads the probability of event B given that event A has occurred.

P(B|A) (option B)

2) Independent events do not affect the outcome of each other

For event A and B to be independent, the probability of event A occurring doesn't affect the the probability of event B occurring

Doesn't affect (option A)

3) Events A and B are independent if the following are satisfied:

P(A|B) = P(A)

P(B|A) = P(B)

The ones that appeared in the option is P(B|A) = P(B) (option A)

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Translate the sentence into an equation.
earnstyle [38]

Answer:

Eight times the sum of a number and 2 is equal to 7.

times = multiply

sum = ()

and = +

SO..

8(w + 2 ) = 7

3 0
2 years ago
A particle is projected with a velocity of <img src="https://tex.z-dn.net/?f=40ms%5E-%5E1" id="TexFormula1" title="40ms^-^1" alt
Katena32 [7]

Answer:

2\sqrt{55}\text{ m/s or }\approx 14.8\text{m/s}

Step-by-step explanation:

The vertical component of the initial launch can be found using basic trigonometry. In any right triangle, the sine of an angle is equal to its opposite side divided by the hypotenuse. Let the vertical component at launch be y. The magnitude of 40\text{ m/s} will be the hypotenuse, and the relevant angle is the angle to the horizontal at launch. Since we're given that the angle of elevation is 60^{\circ}, we have:

\sin 60^{\circ}=\frac{y}{40},\\y=40\sin 60^{\circ},\\y=20\sqrt{3}(Recall that \sin 60^{\circ}=\frac{\sqrt{3}}{2})

Now that we've found the vertical component of the velocity and launch, we can use kinematics equation v_f^2=v_i^2+2a\Delta y to solve this problem, where v_f/v_i is final and initial velocity, respectively, a is acceleration, and \Delta y is distance travelled. The only acceleration is acceleration due to gravity, which is approximately 9.8\:\mathrm{m/s^2}. However, since the projectile is moving up and gravity is pulling down, acceleration should be negative, represent the direction of the acceleration.

What we know:

  • v_i=20\sqrt{3}\text{ m/s}
  • a=-9.8\:\mathrm{m/s^2}
  • \Delta y =50\text{ m}

Solving for v_f:

v_f^2=(20\sqrt{3})^2+2(-9.8)(50),\\v_f^2=1200-980,\\v_f^2=220,\\v_f=\sqrt{220}=\boxed{2\sqrt{55}\text{ m/s}}

3 0
3 years ago
1. Let C be between D and E. Use the Segment addition Postulate to solve for v.
AURORKA [14]

By applying the segment addition postulate, the <u>value of v = 7</u>

  • According to the Segment Addition Postulate, it holds that if point C is between points D and E, therefore:

DC + CE = DE

  • Given that:

DC = 2v-15\\\\CE = 3v-8\\\\DE = 27

  • Therefore, by substitution, we will have the following equation:

(2v-15) + (3v-8) = 27

  • Open the bracket and solve for the value of v.

2v-15 + 3v-8 = 27

  • Add like terms

5v - 23 = 27

  • Add 23 to both sides

5v - 23+ 23 = 27 + 23\\\\5v = 50

  • Divide both sides by 5

v = 10

Therefore, using the segment addition postulate, the <u>value of v = 10</u>

Learn more about the segment addition postulate here:

brainly.com/question/1721582

7 0
3 years ago
5/7x + 15 - 9/14x - 9
muminat

Answer:

1/14x+6

Step-by-step explanation:

I have already learn that

3 0
3 years ago
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vivado [14]
Hey! I don’t know if this is what you mean.. but I tried to understand it.

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73^1

Have a good day :)
3 0
2 years ago
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