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3 years ago

PLS HELP ASAP!!!!!! THANK UUU

Mathematics

1 answer:

Elodia [21]3 years ago

8 0

Answer:

a: is 36

Step-by-step explanation:

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A student factors 15c2 + c – 28 to the following.

Mamont248 [21]

Answer:

C. The expression is not equivalent, but it is completely factored.

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3 years ago

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Please solve the eqution Cos4x + cos2x - 2 =0

horrorfan [7]

cos4x = cos2x

We know that:

cos2x = 1-2cos^2 x

==> cos4x = 1-2cos^2 (2x)

Now substitute:

==> 1-2cos^2 (2x) = cos2x

==> 2cos^2 (2x) + cos2x - 1 = 0

Now factor:

==> (2cos2x -1)(cos2x + 1) = 0

==> 2cos2x -1 = 0 ==> cos2x =1/2 ==> 2x= pi/3

==> x1= pi/6 , 7pi/6

==> x1= pi/6 + 2npi

==> x2= 7pi/6 + 2npi

==> cos2x = -1 ==> 2x= pi ==> x3 = pi/2 + 2npi.

==> x= { pi/6+2npi, 7pi/6+2npi, pi/2+2npi}

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3 years ago

What is the asymptote for the graph of this logarithmic function? f(x) = log3(x – 1)

Pepsi [2]

Answer:

Vertical Asymptote:

$x=1$

Horizontal asymptote:

it does not exist

Step-by-step explanation:

we are given

$f(x)=log_3(x-1)$

Vertical asymptote:

we know that vertical asymptotes are values of x where f(x) becomes +inf or -inf

we know that any log becomes -inf when value inside log is zero

so, we can set value inside log to zero

and then we can solve for x

$x-1=0$

we get

$x=1$

Horizontal asymptote:

we know that

horizontal asymptote is a value of y when x is +inf or -inf

For finding horizontal asymptote , we find lim x-->inf or -inf

$\lim_{x \to \infty} f(x)= \lim_{x \to \infty}log_3(x-1)$

$\lim_{x \to \infty} f(x)=log_3(\infty-1)$

$\lim_{x \to \infty} f(x)=undefined$

so, it does not exist

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3 years ago

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Evaluate -8y - 4x When x = -6. y = 9

sergij07 [2.7K]

-8(9)= -72; -4(-6)= 24; -72+24= -48

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Whats the value of x

Pani-rosa [81]

An outside angle is equal to the sum of the two opposite inside angles.

The two opposite inside angles from X are 63 and 46.

X = 63 + 46 = 109 degrees.

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