Question

how many moles of potassium dichromate (k2cr2o7) are required to prepare a 250-ml solution of with a concentration of 2.16 m?

Answer 1

The moles of potassium dichromate , K₂Cr₂O₇ are required to prepare a 250 mL solution of with a concentration of 2.16 M  is 0.54 mol.

given that :

molarity = 2.16 M

volume = 250 mL = 0.25 L

the molarity is given as :

molarity = number of moles / volumes in L

from this we can calculate the number of moles, we get :

number of moles of K₂Cr₂O₇ = molarity × volume

number of moles of K₂Cr₂O₇ = 2.16 × 0.25

number of moles of K₂Cr₂O₇ = 0.54 mol

Thus, The moles of potassium dichromate , K₂Cr₂O₇ are required to prepare a 250 mL solution of with a concentration of 2.16 M  is 0.54 mol.

To learn more about moles here

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