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3 years ago

Why will a toy train remain still if you push on the engine with

Chemistry

1 answer:

netineya [11]3 years ago

6 0

Explanation:

Because when two equal forces are applied from opposite directions, they "eliminate" each other.

The train would go right if a 3N force was only applied in the right direction, and it would go left if the same force was only applied to the left.

If a 3N force was applied to the right and a 2N force to the left, it would equal a 1N force to the right (3-2=1).

But there it's 3-3=0, so in practice the force is 0N. Therefore the train won't move.

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Question 12 of 35

prohojiy [21]

Answer:

A. all living things are made of cells

Explanation:

A is also called " the cell theory " 1

4 0

3 years ago

How many calories of heat are needed to raise the temperature of 33.0 g of diethyl ether from 14.0 ∘C to 25.0 ∘C ?

Xelga [282]

The amount of heat (in calories) needed to raise the temperature is 324.885 calories

<h3>How to determine the temperature change </h3>

We'll begin by obtaining the temperature change. This can be obtained as followed:

Initial temperature (T₁) = 14 °C
Final temperature (T₂) = 25 °C
Change in temperature (ΔT) = ?

ΔT = T₂ - T₁

ΔT = 25 - 14

ΔT = 11 °C

<h3>How to determine the heat (in Calories)</h3>

The amount of heat needed to raise the temperature can bee obtaimedals follow:

Mass (M) = 33 g
Change in temperature (ΔT) = 11 °C
Specific heat capacity (C) of diethyl ether = 0.895 cal/g°C
Heat (Q) =?

Q = MCΔT

Q = 33 × 0.895 × 11

Q = 324.885 calories

Thus, the amount of heat needed is 324.885 calories

Learn more about heat transfer:

brainly.com/question/10286596

#SPJ1

3 0

1 year ago

Calculate the ph at the equivalence point for the titration of 0.230 m methylamine (ch3nh2) with 0.230 m hcl. the kb of methylam

Vlad1618 [11]

Answer: The pH at the equivalence point for the titration will be 0.65.

Solution:

Let the concentration of $[OH^-]$ be x

Initial concentration of $[CH3NH_2]$ , c = 0.230 M

$CH_3NH_2+H_2O\rightleftharpoons CH_3NH_3^++OH^-$

at eq'm c-x x x

Expression of $K_b$ :

$K_b=\frac{[CH_3NH_3^+][+OH^-]}{[CH_3NH_2]}=\frac{x\times x}{c-x}=\frac{x^2}{c-x}$

Since ,methyl-amine is a weak base,c>>x so $c-x\approx c$ .

$K_b=\frac{x^2}{c}=5.0\times 10^{-4}=\frac{x^2}{0.230 M}$

Solving for x, we get:

$x=1.07\times 10^{-2} M$

Given, HCl with 0.230 M , it dissociates fully in water which means $[H^+]$ = 0.230 M

$[OH^-]=[H^+]$ will result in neutral solution, since $[OH^-]$

Remaining $[H^+]$ after neutralizing $[OH^-]$ ions

$[H^+]_{\text{left in solution}}=[H^+]-[OH^-]=0.230-1.07\times 10^{-2}=0.2193 M$

$pH=-log{[H^+]_{\text{left in solution}}=-log(0.2193)=0.65$

The pH at the equivalence point for the titration will be 0.65.

8 0

4 years ago

Calculate the molarity of a solution that contains 3.11 mol of NaNO3 dissolved in 2.50 L. Enter your answer in the provided box.

rusak2 [61]

Answer:

Molarity of a solution that contains 3.11 mol of NaNO3 is 1,24 M

Explanation:

We understand molarity as the number of moles of solute that are contained in 1 L of solution, then if in a solution of 2.50 L we have 3.11 moles, it remains to calculate how many moles do we have in 1 liter.

2,50 L .......... 3,11 moles

1 L .................. x

X = ( 1 L x 3,11 moles) / 2,50 L = 1,24

8 0

3 years ago

If the Sun suddenly lost all of its gravity, which statement would best describe how the planets would move?

cestrela7 [59]

Answer:

It's B

Explanation:

It's the sun's gravitational pull that keeps our planets revolving around it and as soon as it's gone it's a high chance of it being a pinball machine and everything colliding into each other.

3 0

3 years ago