Answer:
how many liters of 0.150 m hcl would be required to react completely with 8.00 grams of magnesium hydroxide
Explanation:
please give me brainlist and follow
47% yield.
First, let's determine how many moles of ethane was used and how many moles of CO2 produced. Start with the respective atomic weights.
Atomic weight carbon = 12.0107
Atomic weight hydrogen = 1.00794
Atomic weight oxygen = 15.999
Molar mass C2H6 = 2 * 12.0107 + 6 * 1.00794 = 30.06904 g/mol
Molar mass CO2 = 12.0107 + 2 * 15.999 = 44.0087 g/mol
Moles C2H6 = 8 g / 30.06904 g/mol = 0.266054387 mol
Moles CO2 = 11 g / 44.0087 g/mol = 0.249950578 mol
Looking at the balanced equation, for every 2 moles of C2H6 consumed, 4 moles of CO2 should be produced. So at 100% yield, we should have 0.266054387 / 2 * 4 = 0.532108774 moles of CO2. But we only have 0.249950578 moles, or 0.249950578 / 0.532108774 = 0.46973587 =
46.973587% of what was expected.
Rounding to 2 significant figures gives 47% yield.
Beyond the planet Neptune is found a region filled with icy bodies. This region is known as the Kuiper Belt. This holds trillions of objects which is said to be remnants of the early solar system. The region contains comets and dwarf planets.
Answer:
Neutrons play no role in the net charge of an atom, so you can ignore them here.
Proton = 7
Electron = 10
Net Charge = 7 - 10
= -3
Again,
Proton = 3
Electron = 2
Net Charge = 3 - 2
= 1
