Answer:
There is 86.1 mL of KCl needed
Explanation:
<u>Step 1:</u> Data given
Molarity of KCl = 0.244 M
Volume of a 0.210 M Pb(NO3)2 = 50.0 mL = 0.05 L
<u>Step 2:</u> The balanced equation
2KCl(aq) + Pb(NO3)2(aq) -> PbCl2(s) + 2KNO3(aq)
<u>Step 3:</u> Calculate moles Pb(NO3)2
moles Pb(NO3)2 =molarity * volume
moles Pb(NO3)2 = 0.210 M * 0.05 L
moles Pb(NO3)2 = 0.0105 moles
<u>Step 4:</u> Calculate moles of KCl
For 1 mole of Pb(NO3)2 we need 2 moles of KCl
moles KCl required = 0.0105 * 2 =0.0210 moles
<u>Step 5:</u> Calculate volume of KCl
Volume = moles KCl / molarity KCl
V = 0.0210 moles / 0.244 M=0.0861 L = 86.1 mL
There is 86.1 mL of KCl needed
