Question

If 2.0 g of copper(II) chloride react with excess sodium nitrate, what mass of sodium chloride is formed in this double replacement reaction? Write the balanced equation for the reaction first.

Answer 1

Taking into account the reaction stoichiometry, 1.729 grams of NaCl is formed.

Reaction stoichiometry

In first place, the balanced reaction is:

CuCl₂ + 2 NaNO₃ → Cu(NO₃)₂ + 2 NaCl

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

• CuCl₂: 1 mole
• NaNO₃: 2 moles
• Cu(NO₃)₂ : 1 mole
• NaCl: 2 moles

The molar mass of the compounds is:

• CuCl₂: 134.44 g/mole
• NaNO₃: 85 g/mole
• Cu(NO₃)₂ : 187.54 g/mole
• NaCl: 58.45 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

• CuCl₂: 1 mole ×134.44 g/mole= 134.44 grams
• NaNO₃: 2 moles ×85 g/mole= 170 grams
• Cu(NO₃)₂ : 1 mole ×187.54 g/mole= 187.54 grams
• NaCl: 2 moles ×58.45 g/mole= 116.9 grams

Mass of NaCl formed

The following rule of three can be applied: If by stoichiometry of the reaction 134.44 grams of CuCl₂ form 116.9 grams of NaCl, 2 grams of CuCl₂ form how much mass of NaCl?

$mass of NaCl=\frac{2 grams of CuCl_{2}x116.9 grams of NaCl }{134.44grams of CuCl_{2}}$

mass of NaCl= 1.739 grams

Finally, 1.729 grams of NaCl is formed.

Learn more about the reaction stoichiometry:

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