Answer:
The first and second one
Step-by-step explanation:
4(m-5)=4*m-4*5=4m-20
2(2m-10)=2*2m-2*10=4m-20
I'm pretty sure you add all the sides up together. So I think the answer to this would be 61 but I'm not 100% sure
The probability that you picked the fair coin given that the outcome of the toss was heads is 1/3.
There is a one in two chance of drawing the fair coin. The chances of flipping heads again are 1 in 2. As a result, there is a 1 in 4 chance that the coin will land on heads.
There is a one in two chance of drawing the trick coin. The probability of flipping heads is then 2 to 1. As a result, there is a 2 in 4 chance that the coin will land on heads.
When each is multiplied by four, the resulting integers are
fair: 1 and trick: 2
and overall results: 3. (fair and tails is not counted)
The likelihood of a fair coin is one in three.
The likelihood that the chosen coin will show heads and be the fair coin is 33.333%.
To learn more about probability
brainly.com/question/14531945
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Answer:
Step-by-step explanation:
Eliminate the equal sides of each equation and combine.
Solve for 
.
Evaluate 
when .
Answer:
BE = 49
Step-by-step explanation:
In triangle BDC
65^2=56^2+BD^2
65^2-56^2=BD^2
4225-3136=BD^2
1089=BD^2
33=BD
In triangle FDE
65^2=63^2+DE^2
4225-3969=DE^2
256 = DE^2
16=DE
since ED+DB=BE
THEREFORE
16+33=BE
49=BE
