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Charra [1.4K]
1 year ago
11

Which of the following ordered pairs represents the solution to the system given below?2x + y = 204x − 2y = 40

Mathematics
1 answer:
natka813 [3]1 year ago
5 0

The given system is

\mleft\{\begin{aligned}2x+y=20 \\ 4x-2y=40\end{aligned}\mright.

To solve this, we multiply the first equation by 2, then we sum equations.

\mleft\{\begin{aligned}4x+2y=40 \\ 4x-2y=40\end{aligned}\mright.\rightarrow8x=80

Then, we divide the equation by 8.

\begin{gathered} \frac{8x}{8}=\frac{80}{8} \\ x=10 \end{gathered}

Now, we use this value to find <em>y</em>.

\begin{gathered} 2x+y=20 \\ 2(10)+y=20 \\ 20+y=20 \\ y=20-20 \\ y=0 \end{gathered}<h2>Therefore, the solution to the system is (10, 0).</h2>
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sveticcg [70]

The surface are of the right cone is 176 sq.units. Option A) is the correct answer.

<u>Step-by-step explanation</u>:

<u>step 1</u> :

Radius of the cone, <em>r = 4</em>

Height or length of the cone,<em> h = 10</em>

<u>step 2</u> :

Total surface area of right cone = πrh + πr^2

                                                      = (π\times4\times10) + ( π\times4^2)

                                                      = 40π + 16π

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3 years ago
Evaluate 3•r•(t—v) if r=2, t=6, and v=4
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19. The marked price of an oven is 30% above its cost. In a sale, it is
yaroslaw [1]

a) Marked price: $884, Cost: $680

b) 2.5 %

Step-by-step explanation:

a)

Let's call:

P = marked price of the oven

C = cost of the oven

We know that:

- The marked price of the oven is 30% above the cost, which means

P=(1+\frac{30}{100})C=1.30C (1)

- In the sale, the oven is sold at a discount of 25% on its marked price; so the price of the sale is (we call it S)

S=(1-\frac{25}{100})P=0.75P (2)

- We also know that the discount, which is the difference between the makerd price (P) and the discounted price (S) is

P-S=\$221 (3)

Substituting (2) into (3) we find marked price

P-0.75P=\$221\\0.25P=\$221\\P=\frac{221}{0.25}=\$884

Therefore, the cost of the oven is (from eq(1)):

C=\frac{P}{1.30}=\frac{884}{1.30}=\$680

b)

The percentage loss in this situation is given by the difference between cost of the oven and the final price at which the oven is sold.

In this case, we have:

C = $680 (cost of the oven)

The discounted prices is S, and can be f ound using eq(3):

S=P-221=884-221=\$663

Therefore, the oven costs 680$ but it is sold at 663$.

Therefore, we can calculate the percentage loss using the equation:

Loss=\frac{C-S}{C}\cdot 100 = \frac{680-663}{680}\cdot 100 =0.025\cdot 100 = 2.5\%

So, a percentage loss of 2.5%.

4 0
3 years ago
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