What does the slope of a position-time graph measure?

1 answer:

7 0

The number of valence electrons in neutral atoms equals the atom's main group number. A periodic table column can be used to determine an element's main group number.

<h3>What is the meaning of a position time graph?</h3>

The position-time graph depicts the movement of an item across time. Time in seconds is traditionally represented on the x-axis, while object location in metres is plotted along the y-axis. The slope of the position-time graph offers vital information about the object's velocity.

Gravity causes objects in free fall to accelerate. As a result, the free fall motion position-time graph must be curved. This means that objects in free fall begin with a moderate velocity and gradually accelerate, as illustrated by the graph's steep downward curve.

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Determine the kinetic energy of the ball immediately after it is hit. (You must provide an answer before moving to the next part

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The question is incomplete. Here is the complete question.

A baseball palyer hits a 5.1 oz baseball with an initial velocity of 140ft/sat an angle of 40° with the horizontal as shown. Determine

a) The kinetic energy of the ball immediately after it is hit

b) The kinetic energy of the ball when it reaches its maximum height

c) The maximum height above the ground reached by the ball.

Answer: a) KE = 131.64 J

b) KE = 0

c) h = 126 ft

Explanation: <u>Kinetic</u> <u>energy</u> is the energy an object posses due to its motion. It can be calculated as $KE=\frac{1}{2}mv^{2}$

a) Kinetic energy's unit is Joule. So, we have to transform ounce in kg and ft/s in m/s for the units to correspond:

m = 5.1(0.02835)

m = 0.1445 kg

v = 140 ft = 42.67 m/s

Then, kinetic energy is

$KE=\frac{1}{2}(0.1445)(42.67)^{2}$

KE = 131.64 J

Kinetic energy immediately after the ball is hit is 131.64 J.

b) At its maximum height, the ball has its highest potential energy. Because of the law of conservation of energy, when potential energy is maximum, kinetic energy is minimum and vice-versa. So, at the maximum height, kinetic energy is 0.

c) This type of motion is <u>projectile</u> <u>motion</u>. The maximum height on a projectile motion can be determined by

$v_{y}^{2}=v_{0y}^{2}-2g\Delta y$