Answer: Remember speed is distance divided by time, so if he travels 1000 m in 7.045 s, his speed is
(1000 m)/(7.045 s) = 141.9 m/s.
Note there are 1609 metres in a mile, or 1 mi = 1609 m, so m = 1/1609 mi, or
141.9/1609 mi/s = 0.08822 mi/s. Now, note that 1 h = 3600 s, so the speed is
0.08822*3600 mi/h = 317.6 mi/h.
Answer:
490N
Explanation:
According Newton's second law!
\sum Force = mass × acceleration
Fm - Ff = ma
Fm is the moving force
Ff s the frictional force = 100N
mass = 65kg
acceleration = 6m/s²
Required
Moving force Fm
Substitute the given force into thr expression and get Fm
Fm -100 = 65(6)
Fm -100 = 390
Fm = 390+100
Fm = 490N
Hence the force that will cause two cart to move is 490N
The terminal speed of the object falling down is 66.67 m/s.
The terminal speed acquired by the body when,
Weight of the body = Drag force of the body
It is given,
Drag force is directly proportional to the speed,
So,
F = CV
Where F is drag force,
V is the speed,
C is the constant,
So, it can be written as C = F/V.
The weight of the body = mg
The weight of the body = 10m
M is the mass and g is the acceleration due to gravity,
The drag force when the speed is 20m/s.
Drag force = ma
a is the acceleration during the drag force which is given to be 3m/s²,
Drag force = 3m
Now we can write,
F₁/V₁ = F₂/V₂
F₁ is the drag force at 20m/s speed.
F₂ is the weight of the body and V₂ is the terminal speed,
Now, it can be written,
3m/20 = 10m/V₂
V₂ = 66.67 m/s.
So, the terminal speed is 66.67m/s.
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Answer:
true
Explanation:
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Answer:
at t=46/22, x=24 699/1210 ≈ 24.56m
Explanation:
The general equation for location is:
x(t) = x₀ + v₀·t + 1/2 a·t²
Where:
x(t) is the location at time t. Let's say this is the height above the base of the cliff.
x₀ is the starting position. At the base of the cliff we'll take x₀=0 and at the top x₀=46.0
v₀ is the initial velocity. For the ball it is 0, for the stone it is 22.0.
a is the standard gravity. In this example it is pointed downwards at -9.8 m/s².
Now that we have this formula, we have to write it two times, once for the ball and once for the stone, and then figure out for which t they are equal, which is the point of collision.
Ball: x(t) = 46.0 + 0 - 1/2*9.8 t²
Stone: x(t) = 0 + 22·t - 1/2*9.8 t²
Since both objects are subject to the same gravity, the 1/2 a·t² term cancels out on both side, and what we're left with is actually quite a simple equation:
46 = 22·t
so t = 46/22 ≈ 2.09
Put this t back into either original (i.e., with the quadratic term) equation and get:
x(46/22) = 46 - 1/2 * 9.806 * (46/22)² ≈ 24.56 m
