1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ryzh [129]
2 years ago
9

A spring has a spring constant of 5N/cm. What is its extension when loaded with 15N?

Physics
2 answers:
cluponka [151]2 years ago
7 0

Answer:

As per given Information

  • Spring Constant ,K = 5N/cm
  • Force , F = 15N

we have to find the extension when loaded with given magnitude of force.

Using Formulae

\bf \: F = Kx \:

where, x is extension

Putting the value we get

\sf  \twoheadrightarrow \: 15 \:  = 5 \times x \\  \\  \sf  \twoheadrightarrow \:  \frac{15}{5}  = x \\  \\  \sf  \twoheadrightarrow \cancel \frac{15}{5}  = x \\  \\  \sf  \twoheadrightarrow \: 3cm \:  = x

  • <u>Hence</u><u>,</u><u> </u><u>the </u><u>extension</u><u> </u><u>is </u><u>3</u><u> </u><u>cm</u>

So, required option is (d) 3 cm

kakasveta [241]2 years ago
3 0
Pretty sure a it’s d since every cm increases by 5N meaning 3 cm would increase it by 15N
You might be interested in
In case A below, a 1 kg solid sphere is released from rest at point S. It rolls without slipping down the ramp shown, and is lau
mestny [16]

Answer:

the block reaches higher than the sphere

\frac{y_{sphere}} {y_block} = 5/7

Explanation:

We are going to solve this interesting problem

A) in this case a sphere rolls on the ramp, let's find the speed of the center of mass at the exit of the ramp

Let's use the concept of conservation of energy

starting point. At the top of the ramp

         Em₀ = U = m g y₁

final point. At the exit of the ramp

         Em_f = K + U = ½ m v² + ½ I w² + m g y₂

notice that we include the translational and rotational energy, we assume that the height of the exit ramp is y₂

energy is conserved

          Em₀ = Em_f

         m g y₁ = ½ m v² + ½ I w² + m g y₂

angular and linear velocity are related

        v = w r

the moment of inertia of a sphere is

         I = \frac{2}{5} m r²

we substitute

         m g (y₁ - y₂) = ½ m v² + ½ (\frac{2}{5} m r²) (\frac{v}{r})²

         m g h = ½ m v² (1 + \frac{2}{5})

where h is the difference in height between the two sides of the ramp

h = y₂ -y₁

         mg h = \frac{7}{5} (\frac{1}{2} m v²)

         v = √5/7  √2gh

This is the exit velocity of the vertical movement of the sphere

         v_sphere = 0.845 √2gh

B) is the same case, but for a box without friction

   starting point

          Em₀ = U = mg y₁

   final point

          Em_f = K + U = ½ m v² + m g y₂

          Em₀ = Em_f

          mg y₁ = ½ m v² + m g y₂

          m g (y₁ -y₂) = ½ m v²

          v = √2gh

this is the speed of the box

          v_box = √2gh

to know which body reaches higher in the air we can use the kinematic relations

          v² = v₀² - 2 g y

at the highest point v = 0

           y = vo₀²/ 2g

for the sphere

           y_sphere = 5/7 2gh / 2g

           y_esfera = 5/7 h

for the block

           y_block = 2gh / 2g

            y_block = h

       

therefore the block reaches higher than the sphere

         \frac{y_{sphere}} {y_bolck} = 5/7

3 0
3 years ago
What do we call the principal SI units that are used to derive all other SI units? Question 3 options:
Angelina_Jolie [31]

Answer: Base units

The principal SI units that are used to derive all other SI units are called base units. The base units are the units of fundamental quantities e.g.  M L T that is Mass, Length, and Time. All other physical quantities can be written in the fundamental dimension forms. The physical quantities are not measured directly but are build up from the building blocks that are the fundamental quantities which have base units.

5 0
3 years ago
If an object travels at a constant speed in a circular path, the acceleration of the object is:
Vilka [71]

Answer:

1- The acceleration of the object is larger in magnitude the smaller the radius of the circle.

Explanation:

The acceleration of an object in a circular path is

a = \frac{v^2}{r}

As can be seen from the equation, if the radius of the circle is decreases, the magnitude of the acceleration increases.

As for the direction of the acceleration, it is always towards the center, and it is always perpendicular to the direction of the velocity.

6 0
3 years ago
The device is a burner from an electric stove. It is used to transfer heat to a pot by A. Conduction B. Convection C. Radiation
Irina-Kira [14]

I’m pretty positive that it’s A. Conduction. Just refer to the definition of it.

3 0
3 years ago
Read 2 more answers
Which of the following is an example of a lever? knife ramp pencil sharpener wheelbarrow
Kay [80]
I believe it is a knife
5 0
3 years ago
Read 2 more answers
Other questions:
  • Which statement about astrology is not true?
    5·2 answers
  • This is a cell, which is the basic unit of all life. All organs in human bodies are made of cells and require oxygen to survive.
    5·1 answer
  • 1. Why should you use scientific notation when writing big numbers?
    14·1 answer
  • Plz help urgent <br> i will give brainliest
    8·1 answer
  • The quantity of matter in an object. More specifically, it is the measure of the inertia that an object exhibits in response to
    7·1 answer
  • A student on an amusement park ride moves in circular path with a radius of 3.5 m once every 4.5 s. What is the tangential veloc
    9·1 answer
  • An elevator does 9.75 x 10(4) J of work on a person riding up to another floor. How much energy does the person gain
    12·1 answer
  • Minute after minute, hour after hour, day after day, ocean waves continue to splash onto the shore. Explain why the beach is not
    5·1 answer
  • A house is advertised as having 1580 square feet under roof. What is the area of this house in square meters?
    9·1 answer
  • Compared to the wavelength of incident light, diffuse reflection occurs when the size of surface irregularities is?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!