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1 year ago

A spring has a spring constant of 5N/cm. What is its extension when loaded with 15N?

Physics

2 answers:

cluponka [151]1 year ago

7 0

Answer:

As per given Information

Spring Constant ,K = 5N/cm
Force , F = 15N

we have to find the extension when loaded with given magnitude of force.

Using Formulae

$\bf \: F = Kx \:$

where, x is extension

Putting the value we get

$\sf \twoheadrightarrow \: 15 \: = 5 \times x \\ \\ \sf \twoheadrightarrow \: \frac{15}{5} = x \\ \\ \sf \twoheadrightarrow \cancel \frac{15}{5} = x \\ \\ \sf \twoheadrightarrow \: 3cm \: = x$

Hence, the extension is 3 cm

So, required option is (d) 3 cm

kakasveta [241]1 year ago

3 0

Pretty sure a it’s d since every cm increases by 5N meaning 3 cm would increase it by 15N

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