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ryzh [129]
1 year ago
9

A spring has a spring constant of 5N/cm. What is its extension when loaded with 15N?

Physics
2 answers:
cluponka [151]1 year ago
7 0

Answer:

As per given Information

  • Spring Constant ,K = 5N/cm
  • Force , F = 15N

we have to find the extension when loaded with given magnitude of force.

Using Formulae

\bf \: F = Kx \:

where, x is extension

Putting the value we get

\sf  \twoheadrightarrow \: 15 \:  = 5 \times x \\  \\  \sf  \twoheadrightarrow \:  \frac{15}{5}  = x \\  \\  \sf  \twoheadrightarrow \cancel \frac{15}{5}  = x \\  \\  \sf  \twoheadrightarrow \: 3cm \:  = x

  • <u>Hence</u><u>,</u><u> </u><u>the </u><u>extension</u><u> </u><u>is </u><u>3</u><u> </u><u>cm</u>

So, required option is (d) 3 cm

kakasveta [241]1 year ago
3 0
Pretty sure a it’s d since every cm increases by 5N meaning 3 cm would increase it by 15N
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