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2 years ago

A spring has a spring constant of 5N/cm. What is its extension when loaded with 15N?

Physics

2 answers:

cluponka [151]2 years ago

7 0

Answer:

As per given Information

Spring Constant ,K = 5N/cm
Force , F = 15N

we have to find the extension when loaded with given magnitude of force.

Using Formulae

$\bf \: F = Kx \:$

where, x is extension

Putting the value we get

$\sf \twoheadrightarrow \: 15 \: = 5 \times x \\ \\ \sf \twoheadrightarrow \: \frac{15}{5} = x \\ \\ \sf \twoheadrightarrow \cancel \frac{15}{5} = x \\ \\ \sf \twoheadrightarrow \: 3cm \: = x$

Hence, the extension is 3 cm

So, required option is (d) 3 cm

kakasveta [241]2 years ago

3 0

Pretty sure a it’s d since every cm increases by 5N meaning 3 cm would increase it by 15N

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A disk rotates around an axis through its center that is perpendicular to the plane of the disk. The disk has a line drawn on it

natka813 [3]

Answer:

$t = \frac{\sqrt{\omega0^2+2*\theta*\alpha} -\omega0}{\alpha}$

Explanation:

The rotated angle is given by:

$\theta=\omega0*t+1/2*\alpha*t^2$

Since this is a quadratic equation it can be solved using:

$x=\frac{-b \± \sqrt{b^2-4*a*c} }{2*a}$

Rewriting our equation:

$1/2*\alpha*t^2+\omega0*t-\theta=0$

$t = \frac{\±\sqrt{\omega0^2+2*\theta*\alpha} -\omega0}{\alpha}$

Since $\sqrt{\omega0^2+2*\theta*\alpha} >\omega0$ we discard the negative solution.

$t = \frac{\sqrt{\omega0^2+2*\theta*\alpha} -\omega0}{\alpha}$

8 0

3 years ago

Describe the relationship between motion and a reference point.

steposvetlana [31]

Answer:

An object is in motion when its distance from another object is changing. ... A reference point is a place or object used for comparison to determine if something is in motion. An object is in motion if it changes position relative to a reference point. You assume that the reference point is stationary, or not moving.

Explanation:

4 0

3 years ago

Read 2 more answers

A graduated cylinder.measures 15.3 mL. Convert this measurement to DaL

ololo11 [35]

Answer:

0.000153DaL

Explanation:

We have been given:

15.3mL to convert to DaL

DaL is a unit of volume which indicates a decaliter.

This implies that;

1 Da L = 1 x 10²L

So:

1 mL = 1 x 10⁻³L

So 15.3mL will give 15.3 x 10⁻³L

So;

1 x 10²L = 1 DaL

15.3 x 10⁻³L will give $\frac{15.3 x 10^{-3} }{1 x 10^{2} }$ = 15.3 x 10⁻⁵DaL

Therefore, this is 0.000153DaL

5 0

3 years ago

I will be so thankful if u answer correctly!!

polet [3.4K]

Explanation:

The acceleration due to gravity on earth $g_{E}$ is given by

$g_{E} = G\dfrac{M_{E}}{R_{E}^{2}}$

where $G$ = universal gravitational constant

$\:\:\:\:\:\:\:\:\:\:\:\:M_{R}$ = mass of the earth

$\:\:\:\:\:\:\:\:\:\:\:\:R_{E}$ = radius of the earth

Planet Krypton has twice the mass of earth and 3 times the radius so its acceleration due to gravity $g_{K}$ is

$g_{K} = G\dfrac{M_{K}}{R_{K}^{2}}$

$\:\:\:\:\:\: = G\dfrac{(2M_{E})}{(3R_{E})^{2}}$

$\:\:\:\:\;\:= (\dfrac{2}{9})G\dfrac{M_{E}}{R_{E}^{2}}$

$g_{K} = (\dfrac{2}{9})\:g_{E}$

If we multiply both sides by Superman's mass, we get his weights on both planets:

$mg_{K} = (\dfrac{2}{9})\:(mg_{E})$

$W_{K} = (\dfrac{2}{9})\:W_{E} = (\dfrac{2}{9})(900\:N)= 200\:N$

3 0

3 years ago

A space traveller leaves Earth for 10 years at .85c. According to an observer on Earth, how much time has passed?

eduard

First of all, you didn't tell us WHO measured the "10 years".

If it was the people on Earth, then 10 years passed according to them.

If it was 10 years on the space traveler's clock, then the clock in the
OTHER place, like on Earth, is subject to the relativistic 'time dilation'.

If the clocks are moving relative to each other, then the time interval measured
on either clock is equal to the interval measured on the other clock, divided by

√(1 - v²/c²) .

You said that v/c = 0.85 .

v²/c² = (0.85)² = 0.7225

1 - v²/c² = 1 - 0.7225 = 0.2775

√(1 - v²/c²) = √0.2775 = 0.5268

If one clock counts up 10 years, then the other one counts up

(10years) / 0.5268 = 18.983 years 

I believe that's the way to do this, and I'll gladly take your points,
but let me recommend that you get a second opinion before you
actually take off on your 10-year interstellar mission.

8 0

3 years ago