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ryzh [129]
2 years ago
9

A spring has a spring constant of 5N/cm. What is its extension when loaded with 15N?

Physics
2 answers:
cluponka [151]2 years ago
7 0

Answer:

As per given Information

  • Spring Constant ,K = 5N/cm
  • Force , F = 15N

we have to find the extension when loaded with given magnitude of force.

Using Formulae

\bf \: F = Kx \:

where, x is extension

Putting the value we get

\sf  \twoheadrightarrow \: 15 \:  = 5 \times x \\  \\  \sf  \twoheadrightarrow \:  \frac{15}{5}  = x \\  \\  \sf  \twoheadrightarrow \cancel \frac{15}{5}  = x \\  \\  \sf  \twoheadrightarrow \: 3cm \:  = x

  • <u>Hence</u><u>,</u><u> </u><u>the </u><u>extension</u><u> </u><u>is </u><u>3</u><u> </u><u>cm</u>

So, required option is (d) 3 cm

kakasveta [241]2 years ago
3 0
Pretty sure a it’s d since every cm increases by 5N meaning 3 cm would increase it by 15N
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m = mass of the ice added = ?

M = mass of water = 1.90 kg

c_{w} = specific heat of the water = 4186 J/(kg ⁰C)

c_{i}  = specific heat of the ice = 2000 J/(kg ⁰C)

L_{f} = latent heat of fusion of ice to water = 3.35 x 10⁵ J/kg

T_{ii}  = initial temperature of ice = 0 ⁰C

T_{wi} = initial temperature of water = 79 ⁰C

T = final equilibrium temperature = 8 ⁰C

using conservation of heat

Heat gained by ice = Heat lost by water

m c_{w}  (T - T_{ii} ) + m L_{f}  = M c_{w}  (T_{wi} - T)

inserting the values

m (4186) (8 - 0) + m (3.35 x 10⁵ ) = (1.90) (4186) (79 - 8)

m = 1.53 kg

4 0
3 years ago
a 0.15 kg baseball has a momentum of 0.78 kg*m/s just before it lands on the ground. What was the ball's speed just before landi
vovangra [49]

5.2m/s

Explanation:

Given parameters:

Mass of baseball = 0.15kg

Momentum of baseball = 0.78kgm/s

Unknown:

Speed of baseball = ?

Solution:

The momentum of the baseball is a function of the product of the mass and velocity. It is a vector quantity:

        Momentum = mass x velocity

 Since the speed of the ball is unknown:

           Velocity  =  \frac{momentum }{mass}

                           = \frac{0.78}{0.15}

                           = 5.2m/s

The speed of the baseball before it lands is 5.2m/s

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The center of a moon of mass m is a distance D from the center of a planet of mass M. At some distance x from the center of the
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Answer:

x = D (M/M-m) 2.41

Explanation:

a) Let's apply Newton's second law to find the summation of force, where each force is given by the law of universal gravitation

        F = g m₁m₂ / r²

        Σ F = 0

       F1- F2 = 0

       F1 = F2

We set the reference system in the body of greatest mass (M) the planet

       F1 = g m₁ M / x²

       F2 = G m1 m / (D-x)²

      G m₁ M / x² = G m₁ m / (D-x)²

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      MD² -2MD x + M x² = m x²

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We solve the second degree equation

     x = [2MD  ±√ (4M²D² - 4 (M-m) MD²)] / 2 (M-m)

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     x = D {M  ±  Ra (2M²-mM)} / (M-m)

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    x = D (M / (M-m)) (1 ±√ (2-m/M)

Let's analyze this result, the value of M-m >> 1, so if we take the negative root, the value of x would be negative, it is out of the point between the two bodies, so the correct result must be taken with the positive root

 

    x = D (M / (M-m)) (1 + √2)

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b) X = 2/3 D

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