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disa [49]
2 years ago
9

99% of all confidence intervals with a 99% confidence level should contain the population parameter of interest. true or false

Mathematics
1 answer:
tester [92]2 years ago
6 0

The statement that 99% of all confidence intervals with a 99% confidence level should contain the population parameter of interest is false.

A confidence interval (CI) is essentially a range of estimates for an unknown parameter in frequentist statistics. The most frequent confidence level is 95%, but other levels, such 90% or 99%, are infrequently used for generating confidence intervals.

The confidence level is a measurement of the proportion of long-term associated CIs that include the parameter's true value. This is closely related to the moment-based estimate approach.

In a straightforward illustration, when the population mean is the quantity that needs to be estimated, the sample mean is a straightforward estimate. The population variance can also be calculated using the sample variance. Using the sample mean and the true mean's probability.

Hence we can generally infer that the given statement is false.

To learn more about confidence intervals visit:

brainly.com/question/24131141

#SPJ4

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4. Which of the following is not a prime number? A. 19 B. 11 C. 5 D. 24
Anvisha [2.4K]

Answer:

D. 24

Step-by-step explanation:

A prime number is a number that only has 2 factors, which is 1 and itself. In other words, a prime number is only divisible by 1 and itself.

19 is a prime number, because it is only divisible by 1 and itself.

11 is also a prime number because it is only divisible by 1 and itself.

5 is also a prime number because it is only divisible by 1 and itself.

24 is not a prime number because it is divisible by 1 and itself, but it is also divisible by 2, 3, 4, 6, 8, and 12.

The answer is D.

5 0
4 years ago
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Use expressions for odd integers to confirm the conjecture that the product for two odd integers is an odd integer.
Mandarinka [93]

k, n - integers  

2k+1  - an odd integer

2n+1  - another odd integer

The product of them:

  (2k + 1)(2n + 1) =

= 4kn + 2k + 2n + 1 =

= 2(2kn + k + n) + 1

The product of integers (2kn) is integer

and the sum of them (2kn+k+n) also is integer

So  (2k + 1)(2n + 1)  = 2(2kn + k + n) + 1  is an odd integer

4 0
4 years ago
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Answer:A hope this helped
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For the answer to the question above,<span> I will show my solution below.</span><span>
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10. Find the values of x and y.
iragen [17]

Answer:

Could you please provide the question?

Step-by-step explanation:

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