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Lemur [1.5K]
2 years ago
6

Describe the differences between heat transfer through conduction, radiation, and convection.

Physics
1 answer:
DiKsa [7]2 years ago
8 0

Heat transfer in conduction is slow, heat transfer in convection is faster than conduction and heat transfer in radiation is the fastest.

The heat transfer takes place due to the difference in temperature. Heat transfer occurs between objects by direct contact in conduction. In this, heat transfer occurs through a heated solid object. Heat transfer takes within the fluid in convection. In this process heat transfer takes place due to difference in densities. Heat transfer occurs through electromagnetic waves and without involving particles in radiation. Heat transfer in conduction is slow, heat transfer in convection is faster than conduction and heat transfer in radiation is the fastest.

To learn heat transfer visit the link- brainly.com/question/16055406

#SPJ4

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6 0
3 years ago
A guitar string is 90 cm long and has a mass of 3.5g . The distance from the bridge to the support post is L=62cm, and the strin
nataly862011 [7]

Answer:

v_1 =  301 Hz

v_2 =  601 \ \ Hz

v_3 =  901 \ Hz

Explanation:

From the question we are told that

     The  length of the string is  l = 90 \ cm  =  0.9 \ m

     The mass of the string is  m_s  =  3.5 \ g =0.0035 \ kg

     The  distance  from the bridge to the support post L =  62 \ c m  =  0.62 \ m

    The tension is T  =  540 \ N

Generally the frequency is mathematically represented as

        v  =  \frac{n}{2 * L }  [\sqrt{ \frac{T}{\mu} } ]

Where n is and integer that defines that overtones

i.e  n =   1 is for fundamental frequency

      n =  2   first overtone

       n =3   second overtone

Also  \mu is the linear density of the string which is mathematically represented as

           \mu  =  \frac{m_s}{l}

=>        \mu  =  \frac{0.0035 }{ 0.9 }

=>       \mu  =  0.003889 \  kg/m

So for   n = 1

     v_1  =  \frac{1}{2 *  0.62 }  [\sqrt{ \frac{ 540}{0.003889} } ]

     v_1  = 301 \ Hz

So for  n =  2

     v_2  =  \frac{2}{2 *  0.62 }  [\sqrt{ \frac{ 540}{0.003889} } ]

     v_2  = 601 \ Hz

So for  n =  3

     v_3  =  \frac{3}{2 *  0.62 }  [\sqrt{ \frac{ 540}{0.003889} } ]

     v  =901  \ Hz

     

       

5 0
4 years ago
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