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igor_vitrenko [27]
2 years ago
14

3. A model rocket takes 0.05 seconds to speed up from rest to its maximum velocity of 80 m/s.

Physics
2 answers:
Bezzdna [24]2 years ago
8 0

<u>Answer:</u>

<em>The acceleration of the rocket during launch is 1600 ms^-^2.</em>

<u>Explanation:</u>

The rocket works on the principle of Newton’s third law which states that every action has an equal and opposite reaction. The average thrusting force from the momentum is given as  

F= \frac{\Delta p} {\Delta t}

Here Δp is the change in momentum during the process of launching and Δt is the time taken by the rocket to attain its maximum speed for launching.

We also know that p = mv and F = ma from Newton’s second law of motion.

mass \times acceleration=\frac  {(mass \times \Delta velcoity)}  {\Delta time}

As the mass of the rocket will be constant during launching so Δp will have only variation in velocity. Thus the acceleration during launch of rocket will be

acceleration = \frac{80}{0.05}= 1600 ms^-^2

<em>Thus the launching acceleration is 1600 ms-2. </em>

nikklg [1K]2 years ago
7 0

Answer:

1600 \frac{m}{s^2}

Explanation:

Acceleration is defined as the change in velocity divided by the time it took to produce such change. The formula then reads:

a = \frac{change-in-velocity}{time} = \frac{Vf-Vi}{t}

Where Vf is the final velocity of the object, (in our case 80 m/s)

Vi is the initial velocity of the object (in our case 0 m/s because the object was at rest)

and t is the time it took to change from the Vi to the Vf (in our case 0.05 seconds.

Therefore we have:

a = \frac{80 m/s - 0 m/s}{0.05 sec} = 1600 \frac{m}{s^2}

Notice that the units of acceleration in the SI system are \frac{m}{s^2} (meters divided square seconds)

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A ball is released from a tower at a height of 100 meters toward the roof of another tower that is 25 meters high. The horizonta
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-- During the time the ball is flying from the high roof to the low roof,
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75 m = (4.9 m/s²) · (time)²

Time² = (75 m) / (4.9 m/s²)
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3 years ago
Charge of uniform density (0.30 nC/m2) is distributed over the xy plane, and charge of uniform density (−0.40 nC/m2) is distribu
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Answer: E = 39.54 N/C

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E = \frac{\sigma}{2\epsilon_{0}}

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Calculating resulting electric field:

E=E_{1} - E_{2}

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8 0
3 years ago
A person jogs at an average velocity of 3 m/s West. How long will it take this person to run a 30-meter city block?​
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Answer:

It will take the person 10 seconds to run a 30-meter city block.

Explanation:

To solve this problem, we must remember the formula for velocity:

velocity = displacement/time

If we plug in the values that we are given, we get:

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We can see from the above equation that our answer should be in seconds, so we can get rid of the units to simplify the equation slightly.

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Next, we can multiply both sides by t:

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Therefore, the correct answer is 10 s.

8 0
3 years ago
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