Which vector correctly indicates the direction of centripetal acceleration experienced by the car?

Which<br> factors will increase the speed of a sound wave in the air?

Dafna11 [192]

A higher temperature, stiffer materials, and less dense materials increase the speed of sound.

7 0

4 years ago

A geologist wants to locate a horizontal coal bed on a soil-covered slope where soil creep is active. a distinctive sandstone be

Schach [20]

We are ask to know where is the location of the coal bed, in this given sentence when you need to analyze every words just to know where is the coal bed located.

To my understanding the coal bed is located just above the highest piece of sandstone seen in the soil.

7 0

3 years ago

An elevator suspended by a vertical cable is moving downward at a constant speed. The tension in the cable must be A) greater th

True [87]

Answer:

(C) because the elevator is not accelerating

Note F = M a = M g (the resultant force on the elevator is due to gravity)

or Fup = Fc the force exerted on the elevator by the cable

and Fdown = Fe the force exerted on the elevator by gravity

F = M a = Fup - Fdown = zero resultant force on elevator

8 0

3 years ago

A 110 kg tackler moving at 2.5m/s meets head on (and holds on to) an 82 kg halfback moving at 5.0m/s. what will be their mutual

Leona [35]

Answer:

0.7 m/s

Explanation:

We can solve the problem by using conservation of momentum.

Before the collision, the momentum of the first tackler is:

$p_1 = m_1 v_1 =(110 kg)(2.5 m/s)=275 kg m/s$

while the momentum of the second tackler is

$p_2 = m_2 v_2 =(82 kg)(-5.0 m/s)=-410 kg m/s$

Note that we used a negative sign because the direction of the second tackler is opposite to that of the first tackler.

Therefore, the total momentum before the collision is

$p_i = p_1 +p_2 =275 kg m/s -410 kg m/s=-135 kg m/s$

Since the total momentum is conserved, this is also equal to the final total momentum :

$p_f = -135 kg m/s$

Which is also equal to

$p_f = (m_1 +m_2 )v_f$

since the two tacklers continue their motion together with final velocity vf. Re-arranging the previous equation, we can find the the new velocity of the two tacklers:

$v_f = \frac{p_f}{m_1 +m_2}=\frac{-135 kg m/s}{110 kg + 82 kg}=-0.7 m/s$

and the negative sign means the direction is the one of the second tackler.

3 0

4 years ago

Read 2 more answers

What are (a) the charge and (b) the charge density on the surface of a conducting sphere of radius 0.20 m whose potential is 240

Lady bird [3.3K]

Answer:

(a) charge q=5.33 nC

(b) charge density σ=10.62 nC/m²

Explanation:

Given data

radius r=0.20 m

potential V=240 V

coulombs constant k=9×10⁹Nm²/C²

To find

(a) charge q

(b) charge density σ

Solution

For (a) charge q

As

$V_{potential}=kq/r\\ q=rV_{potential}/k\\q=\frac{(0.20)(240)}{9*10^{9} }\\ q=5.333*10^{-9}C\\or\\ q=5.33nC$

For (b) charge density

As charge density σ is given as:

σ=q/(4πR²)

σ=(5.333×10⁻⁹) / (4π×(0.20)²)

σ=10.62 nC/m²

3 0

3 years ago