Write a compound inequality: a quantity of x is greater than 10 and less than 20

Mathematics

1 answer:

Rudiy271 year ago

5 0

The compound inequality is: x<20 and x>10

Given, a quantity of x is greater than 10 and less than 20.

A compound inequality (also known as a compounded inequality) is created when two or more inequalities are coupled with and. One part of an inequality must be true for a value to be a solution to an or inequality. It must make both parts true in order to be the solution to an inequality. X<3 or X>2, for instance.

Divide a compound inequality into two independent ones before attempting to solve it. Choose either a union of sets ("or") and an intersection of sets as the appropriate response ("and"). Then, resolve the graph and all inequalities.

Simply put, a compound inequality is more than one inequality that we want to address simultaneously. When referring to the resolution of both inequalities, we can either use the term "and" or "or."

Learn more about Compound Inequality here:

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student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te

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1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = $\frac{1}{4}$ .

Thus, the probability that the student does not receive version A = $1-\frac{1}{4}$ = $\frac{3}{4}$ .

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

$\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}$