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11 months ago

Two consecutive whole numbers are n-1 and n

Mathematics

1 answer:

Orlov [11]11 months ago

5 0

a. n-(n - 1) = 1

b. n( n - 1) = n² - n

c. (n - 1) + n = 2n - 1

d. (n - 1) + n = 2n - 1

<h3>Solution:</h3>

General Rule for Equation Solving

Remove parentheses and combine like terms to simplify each side of the equation.

To isolate the variable term on one side of the equation, use addition or subtraction.

To find the variable, use multiplication or division.

Given two consecutive numbers , (n - 1) , n

simplifying :

n - (n - 1)

= n -1(n - 1)

= n - n + 1

= 1

multiplying :

n( n -1)

= n² - n

simplifying :

(n-1) + n

= n - 1 + n

= 2n -1

by adding two numbers :

(n - 1) + n

= n -1 + n

= 2n - 1

To learn more about equations refer to :

brainly.com/question/22688504

#SPJ13

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