Question

Two consecutive whole numbers are n-1 and n

Answer 1

a. n-(n - 1) = 1

b. n( n - 1) = n² - n

c. (n - 1) + n = 2n - 1

d. (n - 1) + n = 2n - 1

Solution:

General Rule for Equation Solving

• Remove parentheses and combine like terms to simplify each side of the equation.

• To isolate the variable term on one side of the equation, use addition or subtraction.

• To find the variable, use multiplication or division.

Given two consecutive numbers , (n - 1) , n

simplifying :

n - (n - 1)

= n -1(n - 1)

= n - n + 1

= 1

multiplying :

n( n -1)

= n² - n

simplifying :

(n-1) + n

= n - 1 + n

= 2n -1

by adding two numbers :

(n - 1) + n

= n -1 + n

= 2n - 1

To learn more about equations refer to :

brainly.com/question/22688504

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