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Svetlanka [38]
3 years ago
9

Use the quadratic formula to solve 9x2 + 6x – 17 = 0

Mathematics
1 answer:
USPshnik [31]3 years ago
3 0

The standard form of a quadratic equation is :

ax² + bx + c = 0

And the quadratic formula is:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.

So, first step is to compare the given equation with the above equation to get the value of a, b and c.

So, a = 9, b = 6 and c = - 17.

Next step is to plug in these values in the above formula. Therefore,

x=\frac{-6\pm\sqrt{6^2-4*(9)*(-17)}}{2*9}

=\frac{-6\pm\sqrt{36+612}}{18}

=\frac{-6\pm\sqrt{648}}{18}

=\frac{-6\pm\sqrt{324*2}}{18}

=\frac{-6\pm\sqrt{324}*\sqrt{2}}{18}

=\frac{-6\pm18*\sqrt{2}}{18}

=-\frac{6}{18} \pm\frac{18\sqrt{2}}{18}

=-\frac{1}{3} \pm\sqrt{2}.

So, x = -\frac{1}{3} \pm\sqrt{2}

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The expression will be written as \rm \sqrt[8]{2^5}., the correct option is A.

<h3>What are Exponents?</h3>

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The expression given in the statement can be written as

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The complete question is

Rewrite the rational exponent as a radical by extending the properties of integer exponents.

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