Question

Short Constructed Response: A projectile is shot horizontally off a cliff at a speed of 30 m/s,

Answer 1

Horizontal range of the projectile is 55.41 m..

Maximum height of the projectile is  4.76 m.

Given parameters:

Initial speed of the projectile; u = 30 m/s.

Time of flight; T = 2 s.

We have to find,

Horizontal range of the projectile; R =?

Maximum height of the projectile; H =?

We know that,

Time of flight; T = 2u sinθ/g

⇒ 2 = (2×30× sinθ/10)

⇒ sinθ = 1/3

⇒θ = 19°.

So, Horizontal range of the projectile; R = u²sin2θ/g

= (30² × sin (2×19°)/10)

= 55.41 m.

So, answer of part A is 55.41 m.

Maximum height of the projectile; H =  u²sin²θ/2g

= 30² × sin²19°/(2×10)

= 4.76 m.

So, answer of part B is 4.76 m.

Learn more about projectile motion here:

brainly.com/question/11049671

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