Answer:
hello the diagram relating to this question is attached below
a) angular accelerations : B1 = 180 rad/sec,  B2 = 1080 rad/sec
b) Force exerted on B2 at P = 39.2 N
Explanation:
Given data: 
 Co = 150 N-m , 
<u>a) Determine the angular accelerations of B1 and B2 when couple is applied</u>
at point P ; Co = I* ∝B2' 
                 150  = ( (2*0.5^2) / 3 ) * ∝B2 
∴ ∝B2' = 900 rad/sec 
hence angular acceleration of B2 = ∝B2' + ∝B1 = 900 + 180 = 1080 rad/sec
at point 0 ; Co = Inet * ∝B1
                   150 = [ (2*0.5^2) / 3  + (2*0.5^2) / 3  + (2*0.5^2) ] * ∝B1
∴ ∝B1 = 180 rad/sec
hence angular acceleration of B1 =  180 rad/sec
<u>b) Determine the force exerted on B2 at P</u>
T2 = mB1g + T1  -------- ( 1 )
where ; T1 = mB2g  ( at point p ) 
                  = 2 * 9.81 = 19.6 N
back to equation 1 
T2 = (2 * 9.8 ) + 19.6 = 39.2 N 
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Answer:
1.68 s
Explanation:
From newton's equation of motion,
a = (v-u)/t.................................. Equation 1
Making t the subject of the equation
t =(v-u)g............................. Equation 2
Where t = time taken for the bowling pin to reach the maximum height, v = final velocity bowling pin, u = initial velocity of the bowling pin, g = acceleration due to gravity.
Note: Taking upward to be negative and down ward to be positive,
Given: v = 0 m/s ( at the maximum height), u = 8.20 m/s, g = -9.8 m/s²
t = (0-8.20)/-9.8
t = -8.20/-9.8
t = 0.84 s.
But,
T = 2t
Where T = time taken for the bowling pin to return to the juggler's hand.
T = 2(0.84)
T = 1.68 s.
T = 1.68 s
 
        
             
        
        
        
Answer: affect organisms 
hope this helps you out .
        
             
        
        
        
Answer:
a)
b)
Explanation:
Given:
mass of bullet, 
compression of the spring, 
force required for the given compression, 
(a)
We know
 
where:
a= acceleration


we have:
initial velocity,
Using the eq. of motion:

where: 
v= final velocity after the separation of spring with the bullet. 


(b)
Now, in vertical direction we take the above velocity as the initial velocity "u"
so,

∵At maximum height the final velocity will be zero

Using the equation of motion:

where:
h= height
g= acceleration due to gravity


is the height from the release position of the spring.
So, the height from the latched position be:


