The coefficient of friction between the soap and the floor is 0.081
If Juan steps on the soap with a force of 493 N, this is her weight, W. This weight also equals the normal reaction on the floor, N.
We know that frictional force F = μN where μ = coefficient of friction between soap and floor.
So, μ = F/N
Since F = 40 N and N = W = 493 N,
μ = F/N
μ = 40 N/493 N
μ = 0.081
So, the coefficient of friction between the soap and the floor is 0.081
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Answer:
orbital period increased by a factor of 2.83 unit
Explanation:
Given.
planet’s orbital period, T, and the planets mean distance from the sun, A, in astronomical units, AU
T²= A³
If A is increased by a factor of 2 , .
Then T will be increase with the factor of √2³ = 2.83
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