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Irina18 [472]
4 years ago
14

A compound has a molecular weight of 12.124 atomic mass units and the empirical formula C3H40. What is the molecular formula of

the
compound?
Chemistry
1 answer:
stepladder [879]4 years ago
3 0

Answer:

the empirical formula gives the simplest ratio of whole numbers of components in the compound. Molecular formula gives the actual composition of elements in the compound.

Explanation:

empirical formula - CH₂O

Mass of one empirical unit = 12 + (1x2) + 16 = 30 a.m.u

We have to next calculate how many empirical units make up the molecular formula. For that we have to divide molecular mass by mass of one empirical unit.

Number of empirical units = 180 a.m.u / 30 = 6

There are 6 empirical units 

Therefore molecular formula = 6 x(CH₂O) = C₆H₁₂O₆

Molecular formula = C₆H₁₂O₆

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Which two columns have identical data? What do these two columns suggest about the identity of elements?
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Answer:

Explanation:

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Which pair of atoms forms a nonpolar covalent bond? which pair of atoms forms a nonpolar covalent bond? na and cl c and o n and
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Types of Bonds can be predicted by calculating the difference in electronegativity.

If, Electronegativity difference is,

 

                Less than 0.4 then it is Non Polar Covalent

                

                Between 0.4 and 1.7 then it is Polar Covalent 

            

                Greater than 1.7 then it is Ionic

 

For Na and Cl,

                    E.N of Chlorine       =   3.16

                    E.N of Sodium        =   0.93

                                                   ________

                    E.N Difference             2.23          (Ionic Bond)


For C and O,

                    E.N of Oxygen       =   3.44

                    E.N of Carbon        =   2.55

                                                   ________

                    E.N Difference             0.89          (Polar Covalent Bond)


For N and Cl,

                    E.N of Chlorine      =   3.16

                    E.N of Notrogen     =   3.04

                                                   ________

                    E.N Difference             0.12           (Non-Polar Covalent Bond)


For B and O,

                    E.N of Oxygen        =   3.44

                    E.N of Boron           =   2.04

                                                   ________

                    E.N Difference             1.40          (Polar Covalent Bond)

8 0
4 years ago
Read 2 more answers
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