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1 year ago

When aqueous magnesium chloride reacts with liquid bromine

Chemistry

1 answer:

Bingel [31]1 year ago

3 0

Word equation: magnesium chloride + bromine -> magnesium bromide + chlorine
balance equation: MgCl2 + 2Br -> MgBr2 + 2Cl

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Using any data you can find in the ALEKS Data resource, calculate the equilibrium constant K at 30.0 °C for the following reacti

gayaneshka [121]

Answer : The value of $K$ for this reaction is, $2.6\times 10^{15}$

Explanation :

The given chemical reaction is:

$CH_3OH(g)+CO(g)\rightarrow HCH_3CO_2(g)$

Now we have to calculate value of $(\Delta G^o)$ .

$\Delta G^o=G_f_{product}-G_f_{reactant}$

$\Delta G^o=[n_{HCH_3CO_2(g)}\times \Delta G^0_{(HCH_3CO_2(g))}]-[n_{CH_3OH(g)}\times \Delta G^0_{(CH_3OH(g))}+n_{CO(g)}\times \Delta G^0_{(CO(g))}]$

where,

$\Delta G^o$ = Gibbs free energy of reaction = ?

n = number of moles

$\Delta G^0_{(HCH_3CO_2(g))}$ = -389.8 kJ/mol

$\Delta G^0_{(CH_3OH(g))}$ = -161.96 kJ/mol

$\Delta G^0_{(CO(g))}$ = -137.2 kJ/mol

Now put all the given values in this expression, we get:

$\Delta G^o=[1mole\times (-389.8kJ/mol)]-[1mole\times (-163.2kJ/mol)+1mole\times (-137.2kJ/mol)]$

$\Delta G^o=-89.4kJ/mol$

The relation between the equilibrium constant and standard Gibbs, free energy is:

$\Delta G^o=-RT\times \ln K$

where,

$\Delta G^o$ = standard Gibbs, free energy = -89.4 kJ/mol = -89400 J/mol

R = gas constant = 8.314 J/L.atm

T = temperature = $30.0^oC=273+30.0=303K$

$K$ = equilibrium constant = ?

Now put all the given values in this expression, we get:

$-89400J/mol=-(8.314J/L.atm)\times (303K)\times \ln K$

$K=2.6\times 10^{15}$

Thus, the value of $K$ for this reaction is, $2.6\times 10^{15}$

4 0

3 years ago

PLZ HURRY

Oxana [17]

Answer:

Explanation:

3 0

2 years ago

Read 2 more answers

Colorimetric methods of analysis are based on having a reagent that changes _____________ as a function of the concentration of

GREYUIT [131]

Colorimetric methods of analysis make use of Color changes in reagents to decipher the concentration of solutions.

Therefore, color completes the sentence

<h3>Colourimetric analysis</h3>

Generally, Colorimetric analysis is used to know the concentration of a chemical element in a solution while using colour indicators or reagents.

Therefore

Colorimetric methods of analysis are based on having a reagent that changes Color as a function of the concentration of the analyte.

Color

For more information on Compound

brainly.com/question/704297

3 0

1 year ago

Isobutyl propionate is the substance that provides the flavor for rum extract. combustion of a 1.152 g sample of this carbon-hyd

Ulleksa [173]

Answer;

C7H14O2

Solution;

Isobutyl contains , oxygen, carbon and hydrogen (total mass is 1.152 g)

Mass of carbon = 12/44 × 2.726 g

= 0.743455 g

Mass of Hydrogen = 2/18 × 1.116 g

= 0.124 g

Mass of oxygen = 1.152 - (0.7435 + 0.124)

= 0.2845 g

Moles of carbon ; 0.7435/12 = 0.06196 moles

Moles of hydrogen; 0.124/1 = 0.124 moles

Moles of oxygen; 0.2845/16 = 0.01778 moles

Ratios ; 0.06196/0.01778 ; 0.124/0.01778 : 0.01778/0.01778

= 3.5 : 7.0 : 1

To make them whole numbers ; we multiply the ratios by 2 to get;

(3.5 : 7.0 : 1 )2 = 7 : 14 : 2

Thus, the empirical formula of Isobutyl propionate is C7H14O2

4 0

2 years ago

0.00099989<br> 3 sig figs, scientific notation

mixas84 [53]

1.00*10^3
You’d need to lower the exponent because rounding to 3 sig figs changes the 9’s to - 1000. Keep the 0’s.

5 0

2 years ago