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9966 [12]
3 years ago
12

A solid metal oxide crystallizes in a cubic unit cell. In the unit cell there are metal (M) ions on every corner and in the cent

er of every face. Oxide ions (O) are found in half of the tetrahedral holes. What is the empirical formula of this metal oxide?
Chemistry
1 answer:
kotegsom [21]3 years ago
8 0

Answer:

The empirical formula of the solid metal oxide is : MO

Explanation:

M atom is present in the every corner and in the center of every face.

Number of m atoms :

\frac{1}{8}\times 8+\frac{1}{2}\times 6=4

Number of tetrahedral voids in F.C.C = 2n = 2 × 4 = 8

Oxide ion is present in the half of the tetrahedral void

Number oxide ions = \frac{8}{2}=4

The molecular formula of the solid metal oxide is : M_4O_4=MO

The empirical formula represent the lowest number of atoms present in a compound.

The empirical formula of the solid metal oxide is : MO

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Number of moles = 0.636 ÷ 44 = 0.014mole

Since 1 mole of carbon iv oxide contains 1 mole carbon, 0.014 mole of carbon iv oxide is also produced.

Mass of carbon = 0.014 × 12 = 0.173g, where 12 is the a.m.u of carbon.

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1 mole of water has two moles of hydrogen, thus the amount of hydrogen produced = 0.012 × 2 = 0.024mole

Mass of hydrogen produced = 0.024 × 1 = 0.024g

The percentage composition are as follows:

Carbon = 0.173/0.442 × 100 = 39%

Hydrogen = 0.024/0.442 × 100 = 5.43%

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