The name is <span>leukocytes or leucocytes.
Hope this helped!!</span>
Answer:
= 5.26 × 10^-7 M
Explanation:
We know that;
[H3O+][OH-] = 1 x 10^-14
Therefore;
Given; OH− concentration = 1.9x10^−8 M
Then; [H3O+] = (1 x 10^-14)/[OH-]
= (1 x 10^-14)/(1.9x10^−8)
= 5.26 × 10^-7 M
Answer:The IUPAC name of compound would be Hex-3-yn-ol
Explanation:
When butyne is treated with LDA it leads to generation of carbanion on the terminal alkyne.
As LDA is disopropyl amide which happens to be quite a good base and hence it is sufficiently basic to abstract the acidic proton on the terminal alkyne.
So this proton abstraction leads to generation of a carbanion which can now acts as a nucleophile in step 2.
In step 2 the generated carbanion attacks the strained epoxide ring to open the strained epoxide ring .The product of step 2 leads to generation of hex-3-yn-1-olate
Further on treating the product formed in step 2 with the dilute acid it leads to the formation of alcohol as the negative charge on oxygen can now be neutralised.
Kindly refer the mechanism for structure of compounds.
steps that are followed in taking a stratified random sample are
i. Take a sample of size n/k from each strata, where n is the sample size and k is the number of strata
iv. Take a systematic sample from the population as a whole. Take random samples from each strata.
Stratified random sampling is a sampling method that divides the population into smaller groups called layers. Groups or hierarchies are organized based on the common characteristics or attributes of the members in the group. The process of dividing the population into groups is called hierarchization.
Stratified Random Sample Example:
Suppose a research team wants to determine a GPA for a college student in the United States. The research team is having a hard time collecting data from all 21 million college students. We decided to use 4,000 students to extract a random sample of the population.
Learn more about stratified random sample here: brainly.com/question/24466382
#SPJ4